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Svetllana [295]
2 years ago
7

Old Faithful geyser in Yellowstone National Park shoots water every hour to a height of 40.0 m. With what velocity does the wate

r leave the ground? (Disregard air resistance. g 9.81 m/s) a. 7.00 m/s c. 28.0 m/s d. 14.0 m/s b. 19.8 m/s 30.) A moderate force will break an egg. However, an egg dropped on the road usually breaks, while one dropped on the grass usually does not break because for the egg dropped on the grass, a. the b. the change in momentum is greater. time interval for stopping is greater. the change in momentum is less the time interval for stopping is less. . c. d.
Physics
2 answers:
Alika [10]2 years ago
5 0

Answer:

Option C is the answer = 28.0m/s

Option B

Explanation:

Applying the principle of conservation of energy which takes into consideration the total energy of the system , i.e the summation of the kinetic energy, potential energy. the conservation of energy deals with total energy of a system that changes by the transferring of energy to the system or from the system.

from the question,

height of water h = 40m

g = acceleration due to gravity = 9.81m/seconds square

from the addition of the kinetic energy(energy due to motion) and potential energy(energy by virtue of the position of an object) = initial (Kinetic + potential) = final ( kinetic + potential)

(mgh + 1/2mv -square)initial =( mgh + 1/2 mv -square) final

neglecting or eliminating the mass for both the initial and final,

V-square = 2gh = 2 x 9.81 x 40 = 784.8 = 28.01m/s

Phoenix [80]2 years ago
5 0

Answer:

a) v \approx 28.010\,\frac{m}{s}, b) B. Time interval for stopping is greater.

Explanation:

a) The initial velocity is found with the help of the Principle of Energy Conservation:

K = U_{g}

m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{2\cdot g \cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (40\,m)}

v \approx 28.010\,\frac{m}{s}

b) According to the Impact Theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Hence, the right answer is option B.

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Calculate the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun
fredd [130]

Answer:

149.34 Giga meter is the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun.

Explanation:

Mass of earth = m = 5.976\times 10^{24} kg

Mass of Sun = M = 333,000 m

Distance between Earth and Sun = r = 149.6 gm =  1.496\times 10^{11} m[/tex]

1 giga meter = 10^{9} meter

Let the mass of the particle be m' which x distance from Sun.

Distance of the particle from Earth = (r-x)

Force between Sun and particle:

F=G\frac{M\times m'}{x^2}=G\frac{333,000 m\times m'}{x^2}

Force between Sun and particle:

F'=G\frac{mm'}{(r-x)^2}

Force on particle is equal:

F = F'

G\frac{333,000 m\times m'}{x^2}=G\frac{mm'}{(r-x)^2}

\frac{x}{r-x}=\sqrt{333,000} = ±577.06

Case 1:

\frac{x}{r-x}=577.06

x = 1.49\times 10^{11} m=149.34 Gm

Acceptable as the particle will lie in between the straight line joining Earth and Sun.

Case 2:

\frac{x}{r-x}=-577.06

x = 1.49\times 10^{11} m=149.86 Gm

Not acceptable as the particle will lie beyond on line extending straight from the Earth and Sun.

3 0
2 years ago
One of the great dangers to mountain climbers is an avalanche, in which a large mass of snow and ice breaks loose and goes on an
sammy [17]

Answer:

Explanation:

The acceleration of an object down a slope (neglecting friction, µ = 0) is:

a = g × sin θ

Where,

g is the acceleration due to gravity and θ is the angle of the slope.

a = (9.8 × sin (21.5º)

= 3.592 m/s²

Using equations of motion,

S = ut + 1/2at²

Since, u = 0,

S = 1/2at²

347 = 1/2 × (3.592)t²

t² = 193.21

= sqrt(193.21)

= 13.9 s.

5 0
2 years ago
An egg falls from a nest at a height of 4m. What speed will it have when it is 1m from the ground? Neglect air resistance and ta
Zolol [24]

Answer: 7.66 m/s

Explanation:

This situation is related to free fall (vertical motion). Hence, this can be considered a one-dimension problem and we can use the following equation:

V^{2}=V_{o}^{2}+2gd

Where:

V is the final velocity of the egg at the asked height

V_{o}=0 m/s is the initial velocity of the egg

g=9.8 m/s^{2} is the acceleration due gravity

d=4 m- 1m= 3m is the distance at which the egg is from the nest, when it is 1 m from the ground

Isolating V:

V=\sqrt{V_{o}^{2}+2gd}

Substituting the known values:

V=\sqrt{2(9.8 m/s^{2})(3 m)}

V=7.66 m/s This is the final velocity of the egg

3 0
2 years ago
A wave travels through a medium at 251 m/s and has a wavelength of 5.10 cm. What is its frequency? What is its angular frequency
allochka39001 [22]

Explanation:

It is given that,

Speed of a wave, v = 251 m/s

Wavelength of the wave, λ = 5.1 cm = 0.051 m

(1) The frequency of the wave is given by :

\nu=\dfrac{v}{\lambda}

\nu=\dfrac{251\ m/s}{0.051\ m}

\nu=4921.56\ Hz

(2) Angular frequency of the wave is given by :

\omega=2\pi\nu

\omega=2\pi\times 4921.56\ Hz

\omega=30923.07\ rad/s

(3) The period of oscillation is given by T as :

T=\dfrac{1}{\nu}

T=\dfrac{1}{4921.56}

T = 0.000203 seconds

or

T = 0.203 milliseconds

Hence, this is the required solution.

5 0
2 years ago
Eratosthenes determined the circumference of Earth by conducting an experiment. Put his steps in order as they correlate to the
galben [10]

Solution: The correct order is: C, A, B

The statement of the problem:

How can we prove Earth is round and calculate its circumference?

Hypotheis:

If the sun casts shadows at different angles at the same time of day in different places, we can determine how much Earth curves.

If the Earth was flat, the angle measured at different places at the same time of the day would be same.

Observation:

In Syene, the sun's rays are vertical at noon. At the same time in Alexandria, the rays are 7.2 degrees from the vertical.

5 0
2 years ago
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