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vredina [299]
2 years ago
4

A 40 kg gymnast somersaults into a foam ball pit at a speed of 7 m/s. If the foam applies an average resistive force of 1,000 N,

how far into the pit will the gymnast sink before she stops?
Physics
1 answer:
enot [183]2 years ago
3 0

The distance covered is 0.98 m

Explanation:

Newton's second law states that the force applied on the gymnast is equal to the product between its mass and its acceleration:

F=ma

where in this case,

F = -1000 N is the force applied (negative since it is opposite to the direction of motion)

m = 40 kg is the mass

a is the acceleration

Solving for a,

a=\frac{F}{m}=\frac{-1000}{40}=-25 m/s^2

Since the motion of the gymnast is a uniformly accelerated motion, we can now apply suvat equations:

v^2-u^2=2as

where

v = 0 is the final velocity of the gymnast

u = 7 m/s is the initial velocity

a=-25 m/s^2 is the acceleration

s is the distance through which the gymnast moves before stopping

And solving  for s,

s=\frac{v^2-u^2}{2a}=\frac{0-7^2}{2(-25)}=0.98 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Three balls with the same radius 21 cm are in water. Ball 1 floats, with
Masteriza [31]

Answer:

Explanation:

A )

The ball floats with half of it exposed above the water level . So it must have density half that of water . In other words its density must have been 500 kg / m³

B )

Tension in the ball will be equal to net force acting on the ball

Net force on the ball = buoyant force - weight .

4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1000 - 893 )

= 40.65 x 10⁻⁶ N .

C )Tension in the 3 rd  ball will be equal to net force acting on the ball

Net force on the ball =  weight  - buoyant force

= 4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1320 - 1000  )

=  121.6  x 10⁻⁶ N .

7 0
2 years ago
A 10N force pulls to the right and friction opposes 2N. If the object is 20kg,find the acceleraton.
zmey [24]

Force = mass * acceleration

10 N - 2 N = 20 kg * acceleration

8 N = 20 kg * acceleration

8 / 20 = acceleration

2/5 m/s^2 = acceleration

8 0
2 years ago
Read 2 more answers
The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f
tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0
2 years ago
At a certain instant after jumping from the airplane A, a skydiver B is in the position shown and has reached a terminal (consta
Lubov Fominskaja [6]

Answer:

a=2330

b= 0.223secs

Explanation:

pb=2330m

t=0.223secs

6 0
2 years ago
The eiffel tower has a mass of 7.3 million kilograms and a height of 324 meters. its base is square with a side length of 125 me
uranmaximum [27]

Since the tower base is square with a side length of  125 m,

Therefore,

(125\ m)^2+ (125\ m)^2=31250 m^2

Square root of 31250 = 176.776953 (Diameter) , so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.

The volume of cylinder,

=\pi r^2h=3.14(88.38834765 m)^2\times 324 m =7948168.803\ m^3

Thus, the mass of the air in the cylinder,

=1.225\ kg/m^3 \times 7948168.803\ m^3=9736506.78\ kg

Hence, the mass of the air in the cylinder is this more  than the mass of the tower.


4 0
2 years ago
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