A 732 kg car stopped at an intersection is rear-ended by a 1720 kg truck moving with a speed of 15.5m/s. If the car was in neutr
1 answer:
Answer:
Truck= 6.25 m/s
Car= 21.7 m/s
Explanation:
For elastic collision, the truck's final velocity is given by
The car's final velocity is given by
Where m and u denote masses and velocity respectively, subscripts 1 and 2 denote truck and car respectively.
Substituting 1720 Kg for mass of truck, 732 for mass of car and initial velocity as 15.5 m/s
Therefore, the final velocity of truck is 6.25 m/s while the car's final velocity is 21.7 m/s
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Answer:
A)
B)
Explanation:
Given:
- temperature of air,
- temperature of lungs,
- specific Heat exchanged from the lungs ,
- specific heat of air,
- mass of 1 L air,
- breath rate,
A)
Now,
amount of heat needed to warm the air of lungs to the body temperature:
B)
Amount of heat lost per hour:
<u>No. of breaths per hour:</u>
<u>Now the total loss of energy in 1 hr.:</u>
The gravitational force between two masses m₁ and m₂ is
where
G = 6.67408 x 10⁻¹¹ m³/(kg-s²), the gravitational constant
d = distance between the masses.
Given:
F = 1.5 x 10⁻¹⁰ N
m₁ = 0.50 kg
m₂ = 0.1 kg
Therefore
1.5 x 10⁻¹⁰ N = (6.67408 x 10⁻¹¹ m³/(kg-s²))*[(0.5*0.1)/(d m)²]
d² = [(6.67408x10⁻¹¹)*(0.5*0.1)]/1.5x10⁻¹⁰
= 0.0222
d = 0.1492 m = 149.2 mm
Answer: 149.2 mm
where
G = 6.67408 x 10⁻¹¹ m³/(kg-s²), the gravitational constant
d = distance between the masses.
Given:
F = 1.5 x 10⁻¹⁰ N
m₁ = 0.50 kg
m₂ = 0.1 kg
Therefore
1.5 x 10⁻¹⁰ N = (6.67408 x 10⁻¹¹ m³/(kg-s²))*[(0.5*0.1)/(d m)²]
d² = [(6.67408x10⁻¹¹)*(0.5*0.1)]/1.5x10⁻¹⁰
= 0.0222
d = 0.1492 m = 149.2 mm
Answer: 149.2 mm
De broglie wavelength, , where h is the Planck's constant, m is the mass and v is the velocity.
Mass of hydrogen atom,
v = 440 m/s
Substituting
Wavelength
So the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm