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Black_prince [1.1K]
2 years ago
4

The evaporation losses from a reservoir of constant surface area of 500 acres are 150 acre-ft per day. Of the outflow from the r

eservoir is 50 cfs, determine the change in the water level of the reservoir in a day without inflow.
Engineering
1 answer:
Fofino [41]2 years ago
8 0

Answer:

0.498 ft/day

Explanation:

given,

Surface area, A = 500 acres

evaporation loss, E = 150 acre-ft/day

out flow from reservoir = 50 cfs

   = 50 x 60 x 60 x 24

   = 4.32 x 10⁶ ft³/day

   = 4.32 x 10⁶ ft².ft/day

   =\dfrac{4.32\times 10^6}{43560}\ Acre.ft/day

   = 99.17 acre-ft/day

total moment of the water= evaporation loss + outflow

                                     = 150 + 99.17

                                     = 249.17 acre-ft/day

change in water level per day

      = \dfrac{249.17}{500}

      = 0.498 ft/day

There is loss of 0.498 ft water per day.

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A fatigue test was conducted in which the mean stress was 46.2 MPa and the stress amplitude was 219 MPa.
sleet_krkn [62]

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Minimum stress level =σ₂

The mean stress given as

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2\sigma_m={\sigma_1+\sigma_2}

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Range = 438 MPa

8 0
2 years ago
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