If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume tha
1 answer:
Answer:
t = 1.51 hours
Explanation:
given,
Speed of space shuttle. v = 27800 Km/h
Radius of earth, R = 6380 Km
height of shuttle above earth, h = 320 Km
Total radius of the shuttle orbit
r' = R + h
r' = 6380 + 320
r' = 6700 Km
distance, d = 2 π r
d = 2 π x 6700
t = 1.51 hours
Time require by the shuttle to circle the earth is equal to 1.51 hr.
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Answer:
(D) 96 kg-m/s
Explanation:
Let's start off by first calculating the normal force between the box and the floor.
This will be:
Normal Force = 12 * 9.81 = 117.72 N
We can now use the friction equation to find the frictional force on the box when it is moving:
Frictional force = Coefficient of friction * Normal Force
Frictional force = 0.4 * 117.72 = 47.09 N
Finally, since we have the force on the box, we can find the acceleration:
F = Mass * Acceleration
47.09 = 12 * Acceleration
Acceleration = 3.92 m/s^2
Final speed after 2 seconds:
V= -3.84 m/s
Since we know the initial and final speeds, we can calculate the change in momentum:
Change in momentum = Final Momentum - Initial Momentum
Change in momentum =
Change in momentum = 94.08 kg*m/s
Thus we can see that option (D) is the closest answer.
Answer:
Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).
Explanation:
The sportsman that lifts the stone with a greater mass needs a higher force (El deportista que levanta la piedra con mayor masa necesita una mayor fuerza):
José
Txomin
Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).