Question

A Quaker oatmeal box is a cylinder with a diameter of 10.2 cm and a height of 18.4 cm. What is the volume of the box?

Answer 1

Answer:

a.1503.52 cm^3

b.$v=5575.3cm^{3}$

c. 156.67cm

d. 5059.07m

e.$1.50*10^{4}$

f.5.42

Explanation:

a. from the formula  used to determine the volume of a cylinder which is expressed as

$v=\pi r^{2}h$

where r is the radius. note radius= diameter/2

and h is the height

for a cylinder of 10.2cm diameter, the radius is 10.2/2=5.2cm

and the height 18.4cm

$v =\pi *5.1^{2}*18.4\\ v =1503.52cm^{3}$

b.  from the formula  used to determine the volume of a cylinder which is expressed as

$v =\frac{4}{3} \pi r^{3} \\v=\frac{4}{3} \pi *11^{3} \\v=5575.3cm^{3}$

c. since 1ft=30.48cm

hence 5.14ft will be

5.14*30.48= 156.6672cm

d. since 1mile=1609.34m

hence 3.14356mile will be

3.14356*1609.34=5059.069425m

e. to express 15000 to 3 significant figure we have

$1.50*10^{4}$

f. the distance between two points is expressed as

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}}$

hence for points (1.8,3.0) and (4.5, -1.7) we have

$d=\sqrt{(4.5-1.8)^{2} +(-1.7-3.0)^{2}} \\d=\sqrt{7.29+22.09}\\ d=5.42$