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ohaa [14]
2 years ago
4

Earth's atmosphere is constantly bombarded by cosmic ray protons that originate somewhere in space. If the protons all passed th

rough the atmosphere, assume that each square meter of Earth's surface would intercept protons at the average rate of 1110 protons per second. What would be the electric current intercepted by the total surface area of the planet?
Physics
1 answer:
AlexFokin [52]2 years ago
4 0

Answer:

Explanation:

Each square meter of earth surface intercepts 1110 protons per second.

Total surface of the earth will intercept  no of proton equal to

= 1110 x area of surface

= 1110 x 5.1 x 10¹⁴ m²

= 5661 x 10¹⁴

Total charge

= 1.6 x 10⁻¹⁹ x  5661 x 10¹⁴ coulomb per second

= .09 A .

electric current intercepted by the total surface area of the planet = .09 A.

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Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

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The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

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g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

7 0
2 years ago
An astronaut hits a golf ball of mass m on the Moon, where there is no atmosphere and the acceleration due to gravity is g 6 , w
sasho [114]

Answer:

The magnitude of the average force exerted by the club on the ball during contact = mv/t

Explanation:

Impulse exerted on the ball = Momentum of the ball = mass * velocity = m*v

As we know,  

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Ft = mv

F = mv/t

The magnitude of the average force exerted by the club on the ball during contact = mv/t

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umka2103 [35]

Answer:

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Explanation:

The strength of an electric field E produced by a single charge Q at a distance d from it is given by the formula: E=\frac{k\,Q}{d^2}, where K represents the Coulomb constant.

Since the electric field E is derived from the Coulomb Force per unit charge using a positive test charge, the field's units will be in units of Newtons/Coulomb, and be the formula for the Coulomb electric force between to charges (Q1 and Q2),

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but modified with only one charge showing in the numerator of the expression.

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Illusion [34]

Answer:

Testing

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