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Zanzabum
2 years ago
9

Rana writes a summary about a mass on a spring in simple harmonic motion as it moves upward from the equilibrium position toward

the maximum positive displacement. As the mass moves upward, the velocity is positive and decreasing while the acceleration is negative and decreasing. What error did Rana make?
Physics
2 answers:
Oksanka [162]2 years ago
5 0
The error is in saying that the acceleration is decreasing.


The statements says that the mass is moving from the equilibrium position toward the maximum positive displacement. That means that the mass is moving away from the equilibrium position.


As per the law of Hooke the force exerted by the spring is proportional to the displacement from the equilibrium, which means that the further is the spring from the position of equilibrim the greaer the force.


So, when the mass is moving away from the equilibrium position the force exerted by the spring on the mass is increasing.


Now you should see the mistake, because F = m*a when F (force) increases, a (acceleration) also increases. So it is a mistake saying that the acceleration is decreasing.  
Luba_88 [7]2 years ago
3 0

the answer D the acceleration should be increasing not decreasing

i took the got it right  

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A 70kg man runs at a pace of 4 m/s and a 50g meteor travels at 2 km/s. Which has the most kinetic energy?.
kirill115 [55]

Answer:

the 70kg man

Explanation:

because he has more weight and is moving faster

4 0
2 years ago
Step 8: Observe How Changes in the Speed of the Bottle Affect Beanbag Height
lina2011 [118]

Answer:

When the speed of the bottle is 2 m/s, the average maximum height of the beanbag is <u>0.10</u>  m.

When the speed of the bottle is 3 m/s, the average maximum height of the beanbag is<u> 0.43</u>  m.

When the speed of the bottle is 4 m/s, the average maximum height of the beanbag is  <u>0.87</u> m.

When the speed of the bottle is 5 m/s, the average maximum height of the beanbag is  <u>1.25</u> m.

When the speed of the bottle is 6 m/s, the average maximum height of the beanbag is  <u>1.86</u> m.

Sorry for not answering early on! If anyone in the future needs help, I got these answers from 2020 egenuity, though I can't post the picture for proof. Stay Safe!

6 0
2 years ago
Read 2 more answers
(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i
ddd [48]

Answer:

a) P = 370.993\,kPa, b) F = 25.948\,kN

Explanation:

a) The absolute pressure at a depth of 27.5 meters is:

P = P_{atm} + P_{man}

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 370.993\,kPa

b) The force exerted by the water is:

F = (P - P_{atm})\cdot A

F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}

F = 25.948\,kN

5 0
2 years ago
Read 2 more answers
How much power does it take to lift a 24 kg gift box 6m above the floor in 4 s?
Mrac [35]

Answer:

<h2>5.6kW</h2>

Explanation:

Step one:

given

mass m= 24kg

distance moved= 6m

time taken= 4seconds

Step two:

Required

power

but work done is the force applied at a distance, and the power is the work done time the time taken

Work done= F*D

F=mg

W= mg*D

W=24*9.81*6

W=1412.6J

Power P= work * time

P=1412.6*4

p=5650.5W

P=5.6kW

3 0
1 year ago
Julia jumps straight upward on mars, where the acceleration due to gravity is 3.7\,\dfrac{\text{m}}{\text{s}^2}3.7 s 2 m ​ 3, po
liberstina [14]

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

In this case Final velocity = -3.1 m/s, negative sign indicates it is pointing downward.

acceleration = - 3.7m/s^2 . Negative means acceleration is towards center of planet Mars.

Time taken = 3 seconds

v = u + at\\ \\-3.1 = u-3.7*3\\ \\u = 8 m/s

So jumping velocity of Julia = 8 m/s

6 0
2 years ago
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