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Zanzabum
2 years ago
9

Rana writes a summary about a mass on a spring in simple harmonic motion as it moves upward from the equilibrium position toward

the maximum positive displacement. As the mass moves upward, the velocity is positive and decreasing while the acceleration is negative and decreasing. What error did Rana make?
Physics
2 answers:
Oksanka [162]2 years ago
5 0
The error is in saying that the acceleration is decreasing.


The statements says that the mass is moving from the equilibrium position toward the maximum positive displacement. That means that the mass is moving away from the equilibrium position.


As per the law of Hooke the force exerted by the spring is proportional to the displacement from the equilibrium, which means that the further is the spring from the position of equilibrim the greaer the force.


So, when the mass is moving away from the equilibrium position the force exerted by the spring on the mass is increasing.


Now you should see the mistake, because F = m*a when F (force) increases, a (acceleration) also increases. So it is a mistake saying that the acceleration is decreasing.  
Luba_88 [7]2 years ago
3 0

the answer D the acceleration should be increasing not decreasing

i took the got it right  

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Planetary orbits... are spaced more closely together as they get further from the Sun. are evenly spaced throughout the solar sy
BaLLatris [955]

Answer:

E) are almost circular, with low eccentricities.

Explanation:

Kepler's laws establish that:

All the planets revolve around the Sun in an elliptic orbit, with the Sun in one of the focus (Kepler's first law).

A planet describes equal areas in equal times (Kepler's second law).

The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

T^{2} = a^{3}

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

Therefore, option A and B can not be true.

In the celestial sphere, the path that the Sun moves in a period of a year is called ecliptic, and planets pass very closely to that path.  

4 0
2 years ago
The force sensor measures the force on the sensor due to the bumper, but the cart's momentum change arises from the force on the
Irina-Kira [14]

Answer:

Answered

Explanation:

1 and 3 are necessary

Every bit of force applied to the bumper will be transmitted to the cart EXCEPT for the force needed to accelerate the bumper. This is the net force on the bumper.

If the bumper was heavy then a significant amount of force might be needed to accelerate the bumper so the amount transmitted to the cart would be substantially reduced.

If the net force on the bumper is small then the amount transmitted to the cart is almost the entire force applied.

5 0
2 years ago
Ron fills a beaker with glycerin (n = 1.473) to a depth of 5.0 cm. if he looks straight down through the glycerin surface, he wi
Tju [1.3M]

By law of refraction we know that image position and object positions are related to each other by following relation

\frac{\mu_1}{h_o} = \frac{\mu_2}{h_i}

here we know that

\mu_1 = 1.473

h_o = 5 cm

\mu_2 = 1

now by above formula

\frac{1.473}{5} = \frac{1}{h_i}

h_i = 3.39 cm

so apparent depth of the bottom is seen by the observer as h = 3.39 cm

7 0
2 years ago
During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet)
Serga [27]
T= 24.5 feet per second. That is the velocity it reaches at the end of its fall
7 0
2 years ago
Read 2 more answers
A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d
stira [4]

Answer:600 miles, 12

Explanation: The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

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Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

5 0
2 years ago
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