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lilavasa [31]
2 years ago
3

At the proportional limit, a 2 in. gage length of a 0.500 in. diameter alloy rod has elongated 0.0035 in. and the diameter has b

een reduced by 0.0003 in. The total tension force on the rod was 5.45 kips. Determine the following properties of the material: (a) the proportional limit. (b) the modulus of elasticity. (c) Poisson’s ratio

Physics
1 answer:
topjm [15]2 years ago
5 0

Answer:

a)Proportional limit =  27.756ksi

b) The modulus of elasticity = 15860ksi

c)Poisson ratio = 0.343

Explanation:

The detailed steps and calculation is as shown in the attached file.

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An object is 6.0 cm in front of a converging lens with a focal length of 10 cm.Use ray tracing to determine the location of the
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As we know that

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

here we know that

d_0 = 6 cm

f = 10 cm

now from above equation we have

\frac{1}{d_i} + \frac{1}{6} = \frac{1}{10}

d_i = -15 cm

so image will form on left side of lens at a distance of 15 cm

This image will be magnified and virtual image

Ray diagram is attached below here

8 0
2 years ago
An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
Afina-wow [57]
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity. 

5.5 = (0)(t) + 1/2 (9.81)(t)²
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Now, we may use this time to determine the horizontal distance covered by the parcel by using:
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The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.

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4 0
2 years ago
The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -50 °C and 900 Pa, respect
Sidana [21]

Answer:

T = 273 + (-50) = 273 – 50 = 223 K

R = 188.82 J / kg K for CO2

Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / m^{3}

T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa

Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg / m^{3}

4 0
2 years ago
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You use a slingshot to launch a potato horizontally from the edge of a cliff with speed v0. The acceleration due to gravity is g
Ray Of Light [21]

Answer:

\displaystyle t=\frac{2v_o}{g}

Explanation:

<u>Horizontal Launch</u>

When an object is launched horizontally at a speed vo, it describes a curved called parabola as the speed in the x-direction does not change and the speed in the y-direction increases with time because the gravity makes it return to the ground.

The vertical distance the object (potato) travels downwards is:

\displaystyle y=\frac{gt^2}{2}

The horizontal distance is

x=v_ot

We need to find the time when both distances are equal, thus

\displaystyle \frac{gt^2}{2}=v_ot

Simplifying by t

\displaystyle \frac{gt}{2}=v_o

Solving for t

\displaystyle \boxed{t=\frac{2v_o}{g}}

8 0
2 years ago
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densk [106]

Answer:

The most correct option is;

B. 10 km

Explanation:

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Where:

y = Distance between the two headlights

d = Aperture of observers eye

λ = Wavelength of light

L = Distance between the observer and the headlight

Therefore, from the above solution, the distance between the observer and the headlights is 9386.066 km which is approximately 10 km.

Also we have

sinθ = y/L = 1.22 (λ/d)  

= 1.22 \times \frac{400 \times 10^{-9}}{0.004}

sinθ = 1.22×10⁻⁴ rad

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