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2 years ago

A 0.300 kg mass is attached to

Physics

2 answers:

lesya692 [45]2 years ago

8 0

Answer:

0.98 m/s is the answer!

kherson [118]2 years ago

6 0

Answer:

sqrt(.9576) = v_f

Explanation:

Assuming no friction or air resistance for this.

We can use use conservation of energy for this. Since height isn't changing gravitational potential energy isn't changing, but spring potential energy is.

KE_i + SE_i = FE_f + SE_f

KE is kinetic energy and spring potential energy is SE Initially the mass is not moving so KE_i =0 then SE_i is calculated by .5kx where k is that spring constant and x is the distance from the equilibrium point, so let's plug everything in.

KE_i + SE_i = KE_f + SE_f

.5m(v_i)^2 + .5k(x_i)^2 = .5m(v_f)^2 + .5k(x_f)^2

.5*.3(0)^2 + .5*26.6*(.12)^2 = .5*.3(v_f)^2 + .5*26.6*(.06)^2

.5*26.6*(.12)^2 = .5*.3(v_f)^2 + .5*26.6*(.06)^2

.19152 = .5*.3(v_f)^2 + .04788

.14364 = .5*.3(v_f)^2

.9576 = (v_f)^2

sqrt(.9576) = v_f

Let me know if you couldn't follow the algebra.

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