answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mart [117]
2 years ago
9

What is its characteristic wavelength? [Hint: Recall that the kinetic energy of a moving object is E=12mv2, where m is the mass

of the object and v is the speed of the object.]
Physics
1 answer:
Alchen [17]2 years ago
4 0

Answer:

λ =  1.06 * 10^{-11} m

Explanation:

Using the De Broglie equation, the characteristic wavelength is given by:

λ = \frac{h}{p}

where

h = Planck's constant = 6.626 * 10^{-34} Js.

p = momentum

Momentum, p, can be calculated using:

p =  \sqrt{2Em}

where

m = mass of the electron = 9.11 * 10^{-31} kg

E = Energy of the electron = 13.4 keV = 13.4 * 10^3 * 1.6 * 10^{-19} J = 2.144 * 10^{-15} J

=> p = \sqrt{2 * 2.144 * 10^{-15} * 9.11 * 10^{-31}}

p = \sqrt{3.906 * 10^{-45}}

p = 6.250 * 10^{-23} kgm/s

Therefore, characteristic wavelength, λ, is:

λ =  \frac{6.626 * 10^{-34}}{6.250 * 10^{-23}}

λ =  1.06 * 10^{-11} m

You might be interested in
A steel rod with a length of l = 1.55 m and a cross section of A = 4.45 cm2 is held fixed at the end points of the rod. What is
Blababa [14]

To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

T = 37K

\alpha = 1.17*10^{-5}K^{-1}

Y = 200*10^9Gpa

Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

F = 38526.1N

Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

7 0
2 years ago
What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2
kkurt [141]

Answer:

4.3\cdot 10^{-12} J

Explanation:

The fusion reaction in this problem is

4^1_1H \rightarrow ^4_2He +2e^+

The total energy released in the fusion reaction is given by

\Delta E = c^2 \Delta m

where

c=3.0\cdot 10^8 m/s is the speed of light

\Delta m is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

m(^1_1H)=1.007825u is the mass of one nucleus of hydrogen

m(^4_2 He)=4.002603u is the mass of one nucleus of helium

So the mass defect is:

\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u

The conversion factor between atomic mass units and kilograms is

1u=1.66054\cdot 10^{-27}kg

So the mass defect is

\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg

And so, the energy released is:

\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J

6 0
2 years ago
Dawn and Aram have stretched a slinky between them and begin experimenting with waves. As the frequency of the waves is doubled
m_a_m_a [10]

Answer:

halved

Explanation:

The velocity of the a wave is obtained by multiplying the frequency and wavelength.

v=f\lambda\\\Rightarrow f=\frac{v}{\lambda}\\\Rightarrow \lambda=\frac{v}{f}

Where

v = Velocity

f = Frequency

\lambda = Wavelength

The velocity here is constant. So, if the frequency is doubled the wavelength is halved.

6 0
2 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
2 years ago
Given a triangle with sides X = 6.35 cm and Y = 12.25 cm with an angle of 90 degrees between them, find the length of the hypote
never [62]

Answer:

the hypotenuse = 13.78 cm

Ф = 27.44°

θ = 62.56°

explanation:

4 0
2 years ago
Other questions:
  • Consider a solid, rigid spherical shell with a thickness of 100 m and a density of 3900 kg/m3 . the sphere is centered around th
    5·2 answers
  • What best describes myotibrils
    12·1 answer
  • A fishing boat accidentally spills 3.0 barrels of diesel oil into the ocean. each barrel contains 42 gallons. if the oil film on
    12·1 answer
  • A person driving a car applies the brakes. This produces friction, which stops the car. Into which type of energy is the mechani
    8·2 answers
  • While a gymnast is in the air during a leap, which of the following quantities must remain constant for her?A) Angular momentum
    14·1 answer
  • A baseball hits a car, breaking its window and triggering its alarm which sounds at a frequency of 1210 Hz. What frequency (in H
    5·1 answer
  • Consider a large truck and a small car driving up a straight, steep hill. The truck is moving at 60 miles per hour and the car a
    9·1 answer
  • You are in a rocket moving away from Earth at one-third the speed of light relative to Earth. A friend is on Earth, and an astro
    5·1 answer
  • If the activation energy for a given compound is found to be 103 kJ/mol, with a frequency factor of 4.0 × 1013 s-1, what is the
    10·2 answers
  • The same fluid flows through four different branching pipes. It enters each pipe from the left with the same speed, v0, and flow
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!