The acceleration of the ball when it begins to move is 200 m/s^2.
For the answer tot he questions above, I know this one.
The answers are
<span>-sets 2-3 hours after the sun sets - waxing crescent
-occurs about 3 days before the new moon - waning crescent
-occurs 14 days after the new moon - full moon
-rises at about the time the sun sets - full moon
-visible due south at midnight - full moon
-visible near eastern horizon just before sunrise waning crescent
-visible near western horizon about an hour after sunset waxing crescent</span>
Answer:
F=126339.5N
Explanation:
to find the necessary force to escape we must make a free-body diagram on the hatch, taking into account that we will match the forces that go down with those that go up, taking into account the above we propose the following equation,
Fw=W+Fi+F
where
Fw= force or weight produced by the water column above the submarine.
to fint Fw we can use the following ecuation
Fw=h. γ. A
h=distance
γ=
specific weight for seawater = 10074N / m ^ 3
A=Area
Fw=28x10074x0.7=197467N
w is the weight of the hatch = 200N
Fi is the internal force of the submarine produced by the pressure = 1atm = 101325Pa for this we can use the following formula
Fi=PA=101325x0.7=70927.5N
finally the force that is needed to open the hatch is given by the initial equation
Fw=W+Fi+F
F=Fw-W+Fi
F=197467N-200N-70927.5N
F=126339.5N
<h2>Solution :</h2>
Here ,
• Height of sign post = 30 m
• Distance between signpost and truck = 24 m
Let the
• Top of signpost = A
• Bottom of signpost = B
• The end of truck facing sign post be = C
Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .
Where
• AB = Height of signpost = 30 m
• BC = distance between both = 24 m
• AC = Minimum length of ladder
→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )
→ AC² = (30)² + (24)²
→ AC² = 900 + 576
→ AC² = 1476
→ AC = 38.41875
or AC apx = 38.42
So minimum height of ladder = 38.42
