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2 years ago

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Avery uses a blend of dark chocolate and milk chocolate to make the ice cream topping at her restaurant. She wants to buy 10\,\t

ext{kg}10kg10, start text, k, g, end text more of dark chocolate than milk chocolate, and she needs 150\,\text{kg}150kg150, start text, k, g, end text of chocolate in total for her next order. Let ddd be the number of kilograms of dark chocolate he buys and mmm be the number of kilograms of milk chocolate she buys.

2 answers:

Tcecarenko [31]2 years ago

8 0

Answer: she needs to buy 80kg of

dark chocolate and 70kg of milk chocolate.

Step-by-step explanation:

Let d represent the number of kilograms of dark chocolate that she buys.

Let m represent be the number of kilograms of milk chocolate that she buys.

She wants to buy 10g more of dark chocolate than milk chocolate. This means that

x = y + 10

She needs 150kg of chocolate in total for her next order. This means that

x + y = 150 - - - - - - - - - - - --1

Substituting x = y + 10 into equation 1, it becomes

y + 10 + y = 150

2y + 10 = 150

2y = 150 - 10 = 140

y = 140/2 = 70

x = y + 10 = 70 + 10

x = 80

oksian1 [2.3K]2 years ago

3 0

Answer:

A and B and C and D

Step-by-step explanation:

One of them has to be right

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Rectangle TUVW is on a coordinate plane at T (a, b), U (a + 2, b + 2), V (a + 5, b − 1), and W (a + 3, b − 3). What is the slope

masya89 [10]

Answer:

The correct option is;

A 1

Step-by-step explanation:

The given rectangle TUVW has coordinates T(a, b), U (a + 2, b + 2), V ( a + 5, b - 1) and W (a + 3, b - 3).

Given that the coordinates of T and U are T (a, b), and U (a + 2, b + 2), we have;

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$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where we put (x₁, y₁) = (a, b) and (x₂, y₂) = (a + 2, b + 2), we have;

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Whereby the slope of a line parallel to another line are equal, we have that the slope of the line parallel to the line that contains the side TU is also 1.

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2 years ago

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Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465

disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

$\log _{b} a=\frac{\log a}{\log b}$

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

$x+2=\frac{\log _{10} 15}{\log _{10} 3}$

x + 2 = 2.4649

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2 years ago

Solution to the inequality 16x−33x<37x+27.

astra-53 [7]

<em><u>The solution to the inequality is:</u></em>

$x>\frac{-1}{2}$

<em><u>Solution:</u></em>

Given inequality is:

$16x-33x$

We have to find the solution to given inequality

$\mathrm{Add\:similar\:elements:}\:16x-33x=-17x$

$-17x$

$\mathrm{Subtract\:}37x\mathrm{\:from\:both\:sides}$

$-17x-37x$

Simplify the above inequality

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$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

Remember that, change the inequality sign if you divide or multiply both sides by a negative number

If you divide or multiply both sides by a positive number,the inequality sign will not change

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$\mathrm{Divide\:both\:sides\:by\:}54$

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Thus the solution to inequality is found

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2 years ago

In △ABC, m∠A=15 °, a=10 , and b=11 . Find c to the nearest tenth.

pshichka [43]

Answer:

The answer is:

$\bold{c\approx 20.2\ units}$

Step-by-step explanation:

Given:

In △ABC:

m∠A=15°

a=10 and

b=11

To find:

c = ?

Solution:

We can use cosine rule here to find the value of third side c.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

Putting all the values.

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The answer is:

$\bold{c\approx 20.2\ units}$

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2 years ago