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Leni [432]
2 years ago
14

If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the initial displacement is 2.25 m, and the

change in momentum is 0.58 kg*m/s, how far will it coast back up the ramp before changing directions? Please express your answers with 4 decimal place. _________________________ m
Physics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

L_f = 0.0196

Explanation:

given,

mass of the car,m = 0.2 Kg

height to width of ramp, y/x = 12/75

initial displacement, L_i = 2.25 m

change in momentum, Δp = 0.58 kg.m/s

distance of change in direction of the ramp, L_f = ?

Using equation

\Delta P = m \sqrt{\dfrac{2gy}{x}} (\sqrt{L_i}+\sqrt{L_f})

inserting all the values

0.58 = 0.2\times \sqrt{\dfrac{2\times 9.8\times 12}{75}} (\sqrt{2.25}+\sqrt{L_f})

1.5 + \sqrt{L_f} = 1.64

\sqrt{L_f}=0.14

L_f = 0.0196

The car will cost back up to the distance of 0.0196 m

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Explanation :

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After the collision, both the object sticks over each other and moves with one velocity.

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A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?
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The pull of the moon on Earth's tidal bulge is causing _____. the earth to gradually rotate faster the earth to slowly expand in
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A rock with density 1900 kg/m3 is suspended from the lower end of a light string. When the rock is in air, the tension in the st
wel

Answer:

the tension T2 when the rock is completely immersed is T2 =  29.05 N

Explanation:

from Newton's second law

F= m*a

where F= force , m= mass , a= acceleration

when the rock is suspended ,a=0 since it is at rest. Then

T1 - m*g = 0 , T1= tension when suspended in air , g= gravity

assuming constant density of the rock

m= ρ rock *V , where  ρ rock = density of the rock , V= volume

thus

T1= m*g = ρ rock *g*V

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when the rock is submerged in oil , it receives an upward force that equals the weight of the volume of displaced oil (V displaced). Since it is completely submerged the volume displaced is the volume of the rock V=Vdisplaced  

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F= m*a=0

T2 + ρ oil *g*V displaced - ρ rock *g*V  =0

T2 = ρ rock *g*V - ρ oil *g*V = g*V (ρ rock - ρ oil)

T2 = g*V (ρ rock - ρ oil) = T1/(ρ rock *g) *g * (ρ rock - ρ oil)

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3 0
2 years ago
A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene
Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

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Explanation:

If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

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5 0
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