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lbvjy [14]
2 years ago
3

A mass of 4.133g of sodium carbonate crystals Na2CO3.XH2O (s) was heated gently and 3.533g of anhydrous compound remained.Calcul

ate the value of X.
Chemistry
1 answer:
Masteriza [31]2 years ago
6 0

Answer:

1

Explanation:

From the question, the following were obtained:

Mass of hydrated salt(Na2CO3.XH2O) = 4.133g

Mass of anhydrous salt(Na2CO3) = 3.533g

Mass of water = 4.133 — 3.533 = 0.6g

Next, we convert these grams to moles

MM of Na2CO3 = (23 x 2)+12+(16x3) = 46+12+48) = 106g/mol

Number of mole = Mass /Molar Mass

Number of mole of Na2CO3 = 3.533/106 = 0.033mol

MM of water (H2O) = (2x1) +16 = 2+16 =18g/mol

Number of mole of H2O = 0.6/18 = 0.033mol

Next, we find the ratio of the mole of anhydrous salt to the water. This done below:

Mole of anhydrous : mole of water = 0.033 : 0.033 = 1 : 1

The number of mole of water attached to the salt is 1

The formula of the hydrated salt is CuSO4.H2O

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Classify each property as associated with a liquid that has strong or weak intermolecular forces Drag the appropriate items to t
Ivan

Answer: intermolecular forces are described as forces that either cause attraction or repulsion between neighbouring particles or molecules

Explanation: liquids with strong intermolecular forces has the following properties:

1.) High boiling point

2.) high surface tension

3.) Low viscosity

4.) Low vapour pressure

While liquids with weak intermolecular forces has the following properties:

1.) Low boiling point

2.)low surface tension

3.) High viscosity

4.) High vapour pressure.

3 0
2 years ago
A sample of pure NO2 is heated to 337?C at which temperature it partially dissociates according to the equation2NO2(g)?2NO(g)+O2
tatyana61 [14]

Answer: Kc =5.915.10^{-3}

Explanation: Kc is an equilibrium constant of a chemical reaction and is dependent upon the reagents and products concentration. For this reaction, Kc is:  Kc = \frac{[NO]^{2} .[O2]}{[NO2]^{2} }

To determine each concentration, we have to find each relation:

From the reaction, we know that [NO] = 2[O2] (1)

From the Ideal Gas Law,

P·V=ntotal·R·T

\frac{P}{RT}=\frac{ntotal}{V}

\frac{P}{RT} = \frac{n(NO2)}{V} + \frac{n(NO)}{V} + \frac{n(O2)}{V}

[NO2]+{NO}+[O2] = \frac{0.745}{0.082.610} = 0.015 mol/L

As [NO] = 2[O2]

[NO2]+2[O2]+[O2]=0.015

[NO2] = 0.015 - 3[O2] (2)

To resolve this equation, we will turn towards density of the mixture:

ρ = \frac{m(NO2)+m(NO)+m(O2)}{V}

Substituting mass for molar mass and number of molar,

ρ = M(NO2)·\frac{n(NO2)}{V}+M(NO)·\frac{n(NO)}{V}+M(O2)·\frac{n(O2)}{V}

Knowing the molar mass of each molecule:

ρ = 46·[NO2]+30·[NO]+32·[O2] = 0.525 g/L (3)

Substituting (1), (2) and (3) we have:

46(0.015 - 3[O2])+30(2[O2])+32.[O2]=0.525

32[O2]+60[O2]-138[O2]=0.0525-0.69

-48[O2]= -0.6375

[O2]=13.3.10^{-3}M

Calculating for [NO]

[NO]=2[O2]

[NO]=2.13.3.10^{-3}

[NO]=26.6.10^{-3}M

And finding [NO2],

[NO2]=0.015 - 3[O2]

[NO2]=0.015 - 3.13.3.10^{-3}

[NO2]=39.885.10^{-3}M

So, to calculate Kc:

Kc = (26.6.10^{-3})²· 13.3.10^{-3} / (39.885.10^{-3})²

Kc= 5.915.10^{-3}

The Kc is 5.915.10^{-3}.

6 0
2 years ago
Janine is trying to separate some ethanol from water. Which method should she use does anyone know this
GuDViN [60]

To separate some ethanol from water, Jane needs to use the method of simple distillation.

Simple distillation is a separation method in which two liquids can be separated from each other based on differences in boiling point.

Since water has a higher boiling point than ethanol, ethanol is collected first as the distillation proceeds.

Learn more:  brainly.com/question/2193327

5 0
2 years ago
A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
igomit [66]
<h3>Answer:</h3>

702 mL

<h3>Explanation:</h3>

We are given;

The mass of sodium hydroxide  = 13.20 g

Molarity of H₂SO₄ = 0.235 M

We are required to calculate the volume of the acid required to neutralize the solution of NaOH

<h3>Step 1: Balanced equation for the reaction</h3>

The equation for the reaction between H₂SO₄ and NaOH is given by;

2NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Calculate the number of moles of NaOH</h3>

Number of moles is given by dividing mass by molar mass

Molar mass of NaOH = 40.0 g/mol

Therefore;

Number of moles of NaOH = 13.20 g ÷ 40 g/mol

                                             = 0.33 moles of NaOH

<h3>Step 3: Calculate the number of moles of H₂SO₄ used during the reaction </h3>

From the equation 2 moles of NaOH reacts with 1 mole H₂SO₄

Therefore, the mole ratio of NaOH : H₂SO₄ is 2 : 1

Thus, number of moles of H₂SO₄ = Moles of NaOH ÷ 2

                                                       = 0.33 moles ÷ 2

                                                       = 0.165 moles

<h3>Step 4: Calculate the volume of the H₂SO₄</h3>

Molarity refers to the concentration of a solution in moles per liter

Molarity = Number of moles ÷ Volume

Rearranging the formula;

Volume = Number of moles ÷ Molarity

            = 0.165 moles ÷ 0.235 M

            = 0.702 L

           = 702 mL

Therefore, the volume of 0.235 M acid solution required is 702 ml

8 0
2 years ago
Nickel-63 has a half life of 92 hours. If a
arsen [322]

Answer:

6.25 g of nickel -63 will be left

Explanation:

5 0
2 years ago
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