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balandron [24]
2 years ago
3

Now consider the time to begin at 2.3 min, where [H2O2] = 0.50 M. How much time is required to cut the concentration in half aga

in, in this case from 0.50 M to 0.25 M?
Chemistry
1 answer:
padilas [110]2 years ago
3 0

Answer:

2.3 minutes

Explanation:

The half life of any reaction is the amount of time it takes to consume half of the starting material.

The Half life of a reaction is usually constant for that particular material.

From the question it takes 2.3 min to cut the concentration in half to a concentration of 0.5M

How much time it would then take to cut the concentration in half again, in this case from 0.50 M to 0.25 M?

It's still going to take 2.3 minutes which is the half life.

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What is the driving force in the wittig reaction?
jonny [76]
Formation of strong phosphorous-oxygen bonds drives the Wittig reaction. Phosphorous is extremely oxophilic, meaning that it forms strong bonds with oxygen.
7 0
2 years ago
When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and
Vika [28.1K]
The correct answer is 1. Lose electrons and become positive ions.


I hope my answer was beneficial to you! c:
5 0
2 years ago
Read 2 more answers
A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5×10−9m, and 1.00 ml
Elis [28]

The concentration of the drug stock solution is 1.5*10^-9 M i.e. 1.5 * 10^-9 moles of the drug per Liter of the solution

Therefore, the number of moles present in 1 ml i.e. 1*10^-3 L of the solution would be =  1 *10^-3 L * 1.5 * 10^-9 moles/1 L = 1.5 * 10^-12 moles

1 mole of the drug will contain 6.023*10^23 drug molecules

Therefore, 1.5*10^-12 moles of the drug will correspond to :

    1.5 * 10^-12 moles * 6.023*10^23 molecules/1 mole = 9.035 * 10^11 molecules

The number of cancer cells = 2.0 * 10^5

Hence the ratio = drug molecules/cancer cells

                          = 9.035 *10^11/2.0 *10^5

                          = 4.5 * 10^6

8 0
2 years ago
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Suppose total world energy consumption of fossil fuels, equal to 3×1017 kJ/yr, were to be obtained entirely by combustion of pet
Natasha_Volkova [10]

Answer:

it would definitely be wienerballs1977

Explanation:

fossil fuels x (3x1017kJ/yr) equals out to be wienerballs1977.

thx for the challenge !

3 0
2 years ago
Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the formul
Mars2501 [29]

Answer:

Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).

Explanation:

This is a chemical reaction problem.

In expressing any chemical reaction, we need to understand that there are reactants and products.

  • The reactants are the species on the left hand side that are combining.
  • The products are the species on the right hand side that are formed.
  • Every chemical reaction is obeys the law of conservation of matter i.e equal number of matter on both sides.

Using the statement of this problem, we can deduce that;

 Reactants are Fluorine gas and Calcium metal

  Product is Calcium Fluoride

Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.

                    F₂_{(g)}     +    Ca_{(s)}               →           CaF₂_{(s)}

We can see that equal number of atoms are on both sides of the expression.

7 0
2 years ago
Read 2 more answers
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