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alexandr402 [8]
2 years ago
4

The policy of a particular bank branch is that its ATMs must be stocked with enough cash to satisfy customers making withdrawals

over an entire weekend. The expected average amount of money withdrawn from ATM machines per customer transaction over the weekend is $160 with an expected standard deviation of $34. (Assume that this distribution is normal). Suppose that a random sample of 26 customer transactions is examined and it is observed that the mean withdrawal is $171. Draw a fully justified conclusion based on this setup. Be sure to interpret your p-value.
Chemistry
1 answer:
jolli1 [7]2 years ago
4 0

Solution:

If a random sample of 26 customer transactions indicates that the sample mean withdrawal amount is $171, is there evidence to believe that the population mean withdrawal amount is no longer $160? (Use a 0.05 level of significance.)

Hypotheses: H_{0}: µ = $160

                      H_{1}: µ ≠ $160

Critical Value:

Since population standard deviation is known, use Z statistic.

For a two-tailed test and at the 0.05 level of significance, Z_{cv}= +1.96.

Test Statistics: Decision and Conclusions:

Decision rule: Reject H_{0} if -Z_{Stat}< –1.96 or Z_{Stat}> +1.96.

Since Z_{Stat}= 2.4 > 1.96, reject H_{0}.

There is enough evidence to conclude that the mean amount of cash withdrawn per customer from the ATM machine is not equal to $160.

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Ordinary table sugar is primarily sucrose, which has the chemical formula c12h22o11. calculate the mass percentages of carbon, h
tester [92]
<span>carbon = 42.1% hydrogen = 6.5% oxygen = 51.4% First lookup the molar mass of carbon, hydrogen, and oxygen. mass of carbon = 12.0107 mass of hydrogen = 1.00794 mass of oxygen = 15.999 Now calculate the molar mass of each element in sucrose multiplying the atomic weight of each element by the number of times the element is used. carbon = 12 * 12.0107 = 144.1284 hydrogen = 22 * 1.00794 = 22.17468 oxygen = 11 * 15.999 = 175.989 Calculate the molar mass of sucrose by adding the mass of each element used. 144.1284 + 22.17468 + 175.989 = 342.2921 Finally, calculate the percentage by mass of each element by dividing the mass used for each element by the total mass of sucrose. carbon = 144.1284 / 342.2921 = 0.421068 = 42.1% hydrogen = 22.17468 / 342.2921 = 0.064783 = 6.5% oxygen = 175.989 / 342.2921 = 0.514149 = 51.4%</span>
6 0
2 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
2 years ago
A load of bauxite has a density of 3.11 . If the mass of the load is 220. metric tons, how many dump trucks, each with a capacit
kicyunya [14]

Answer : The number of dump trucks required are, 8

Explanation : Given,

Density of load of bauxite = 3.11g/cm^3

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First w have to calculate the volume of load of bauxite.

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Convert cubic centimeter to cubic yard:

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So,

Volume of load = \frac{1.30795\times 10^{-6}yards^3}{1cm^3}\times (7.07\times 10^7cm^3)

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2 years ago
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mart [117]

Answer:

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Explanation:

Hello,

To solve this question, we'll first of all find the volume of the metal and assuming there's no loss of water by overflow in the container, we'll add the volume of the metal to the volume of the water to get the final volume.

Data;

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The volume of the metal is 12.46mL.

When the metal is added to the container 45mL of water, assuming no water was lost by overflow in the container, the final volume =

Final volume = volume of metal + volume of water

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Final volume = 57.46mL

The final volume of the metal and water is 57.46mL

8 0
2 years ago
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