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qwelly [4]
2 years ago
14

The formation of the iron(III) thiocyanate complex ion is an exothermic equilibrium system. For each change to the system, indic

ate how the concentration of each species in the chemical equation will change to reestablish equilibrium. An up arrow indicates an increase in concentration, a down arrow indicates a decrease in concentration, and leaving it blank means there is no change in the concentration.
Chemistry
1 answer:
Anna35 [415]2 years ago
8 0

Answer:

This question appears incomplete

Explanation:

The equation for the formation of iron(III) thiocyanate complex ion is

Fe³⁺ + SCN⁻ ⇄ Fe(SCN)²⁺

Three factors affect the equilibrium of a reaction

  • temperature
  • pressure (in gases)
  • concentration

Since the formation of Fe(SCN)²⁺ is an exothermic reaction (delta H is negative); an increase in temperature will favor the backward reaction and more reactants will be produced. When the temperature is however reduced, the forward reaction will be favored and more products will be produced.

When the concentration of the reactants increases, the forward reaction is favored and hence more Fe(SCN)²⁺ is produced. However, when the concentration of Fe(SCN)²⁺ decreases, the backward reaction is favored and more reactants are produced.

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Based on the results of this lab, write a short paragraph that summarizes how to distinguish physical changes from chemical chan
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Physical changes occur when the properties of a substance are retained and/or the materials can be recovered after the change. Chemical changes involve the formation of a new substance. Formation of a gas, solid, light, or heat are possible evidence of chemical change.

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2 years ago
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Suppose you are studying the K sp of K C l O 3 , which has a molar mass of 122.5 g/mol, at multiple temperatures. You dissolve 4
Ghella [55]

Answer:

The K sp Value is  K_{sp}=7.40

Explanation:

From the question we are told that

   The of KClO_3 is = 122.5 g/ mol

    The mass of KClO_3 dissolved is m_s = 4.0g

    The volume of solution is  V_s = 12mL = 12*10^{-3}L

The number of moles of KClO_3 is mathematically evaluated as

           No \ of  \ moles  \ = \frac{mass }{Molar \ mass}

Substituting values

                                  = \frac{4}{122.5}

                                  =0.0327\ moles

Generally concentration is mathematically represented as

         concentration = \frac{No \ of \ moles}{volume }

For KClO_3        

               Z= \frac{0.0327}{12*10^{-3}}

                              =2.72 \ mol/L

The dissociation reaction of KClO_3  is

         KClO_3 \ ----> K^{+}_{(aq)} + ClO_3^-_{(aq)}

The solubility product constant is mathematically represented as

                   K_{sp} = \frac{concentration of ionic product }{concentration of ionic reactant }

Since there is no ionic reactant we have

                  K_{sp} = [k^+] [ClO_3^-]

                          = Z^2

                          = 2.72^2

                          K_{sp}=7.40

                         

5 0
2 years ago
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2 years ago
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</span><span>
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</span><span>
</span>₈₁²⁰¹Tl +  ₋₁⁰e →  ₀⁰γ + ₈₀<span>²⁰¹Hg</span>

6 0
2 years ago
How many grams of nano3 would you add to 500g of h2o in order to prepare a solution that is 0.500 molal in nano3?
VARVARA [1.3K]
When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.

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4 0
2 years ago
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