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2 years ago

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Calculate the freezing-point depression and osmotic pressure at 258C of an aqueous solution containing 1.0 g/L of a protein (mol

ar mass 5 9.0 3 104 g/mol) if the density of the solution is 1.0 g/cm3. b. Considering your answer to part a, which colligative property, freezing-point depression or osmotic pres- sure, would be better used to determine the molar masses of large molecules

1 answer:

Tanzania [10]2 years ago

5 0

The osmotic pressure is 0.2 atm

The freezing point depression=2*10^-5 \

Osmotic pressure would be better to determine the molar masses of large molecule as precise number of moles can be known.

Explanation:

The equation for the osmotic pressure is the:

π=MRT

where π= osmotic pressure

M= Molarity , R= Gas constant, T =temperature

M= 1/9*10^4

= 1.1*10^-5 mol/litre

π= MRT

= 1.1*10^-5*0.0826* 298*760 Torr

= 0.20 torr

osmotic pressure= 0.20 atm

ΔTf=Kfm*

= 1.86*1.1.10^-5

=2.06*10^-5

The osmotic pressure would be better to determine the molar mass from the formula π= MRT

When molarity is known molar mass ie easily known as number of moles would be known and multiplied with atomic weight will give molar mass.

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