Answer:
5
Explanation:
54.34+45.66=100.00 (you have to use the .00 because when you add to numbers you keep the number of decimals)
so you get 100.00
all numbers that are not 0 are sig figs so 1 is a sig fig
If a number ends with a 0 after a decimal place that 0 is a sig fig
all numbers between two sig figs are sig figs so that would make all of the numbers sig figs
Answer:
Explanation:
The problem must be addressed through the concepts of electromotive force. By Faraday's law it is defined that
Where
Electromotive Force
N = Number of Loops
A = Area
B = Magnetic Field (chaging through the time)
From this equation and our values, we need to find the time, then we re-arrange the equation
Therefore the time required for the magnetic field to decrease to zero from its maximum value is
Answer:
the function varies linearly with the radius of the disk, so the smallest period is zero for a radius of zero centimeters
Explanation:
This system performs a simple harmonic movement where the angular velocity is given by
w = √ k / I
Where k is the constant recovered from the axis of rotation and I is the moment of inertia of the disk
The expression for the moment of inertia is
I = 1/2 m r²
Angular velocity, frequency and period are related
w = 2π f = 2π / T
Substituting
2π / T = √ k / I
T = 2π √ I / k
T = 2π √ (½ m r² / k)
T = (2π √m / 2k) r
We can see that the function varies linearly with the radius of the disk, so the smallest period is zero for a radius of zero centimeters
Answer:
The right answer is "1010 V/m".
Explanation:
The given values are:
Intensity,
Now,
The electric field's maximum value will be:
= 
On substituting the values in the above formula, we get
= 
= 
= 
This is very good conceptual question and can clear your doubts regarding work-energy theorem.
Whenever force is perpendicular to the direction of the motion, work done by that force is zero.
According to work-energy theorem,
Work done by all the force = change in kinetic energy.
here, work done = 0.
Therefore,
0=change in kinetic energy
This means kinetic energy remains constant.
Hope this helps
