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2 years ago

What do the following have in common: MgCl2, AlF3, CaI2, KCl

Chemistry

2 answers:

arsen [322]2 years ago

8 0

Answer:

They are salts, ionic compounds

Explanation:

To know if they are covalent or ionic we need to check their difference in electronegativity. As an example mgcl2, mg has electronegativity of 1.2 and cl 3 so 3-1.2=1.8 which is bigger than 1.7 means it's ionic therefore they are salts

Kay [80]2 years ago

5 0

They are salts and are all ionic compounds because in the formula one of the element has to have a positive and the other a negative charge.

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If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:

Andrew [12]

Answer:

Mass of CuSO4.H2O obtained: $m_{total}=19.52 g$

Explanation:

The molecular weight of the salt is: $M=159.5 g/mol$

In the solution: 12.5 g of CuSO4

In moles: $n=\frac{12.5 g}{159.5 g/mol}=0.078 mol$

Mass of water:

5 moles of water per mol of salt: $m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g$

Mass of CuSO4.H2O obtained: $m_{total}=12.5 g + 7.02 g=19.52 g$

7 0

2 years ago

the half life of the radioactive element strontium-90 is 29.1 years. If 16 grams of strontium-90 are initially present, how many

8_murik_8 [283]

Answer:

4 g after 58.2 years

0.0156 After 291 years

Explanation:

Given data:

Half-life of strontium-90 = 29.1 years

Initially present: 16g

mass present after 58.2 years =?

Mass present after 291 years =?

Solution:

Formula:

how much mass remains =1/ 2n (original mass) ……… (1)

Where “n” is the number of half lives

to find n

For 58.2 years

n = 58.2 years /29.1 years

n= 2

or 291 years

n = 291 years /29.1 years

n= 10

Put values in equation (1)

Mass after 58.2 years

mass remains =1/ 22 (16g)

mass remains =1/ 4 (16g)

mass remains = 4g

Mass after 58.2 years

mass remains =1/ 210 (16g)

mass remains =1/ 1024 (16g)

mass remains = 0.0156g

8 0

2 years ago

Read 2 more answers

Calculate the mass in grams of each of the following amounts: 1.002 mol of chromium 4.08 x 10-8 mol of neon

Pepsi [2]

Answer:

$Mass_{chromium}=52.1\ g$

$Mass_{neon}=8.23\times 10^{-7}\ g$

Explanation:

Calculation of the mass of chromium as:-

Moles = 1.002 moles

Molar mass of chromium = 51.9961 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1.002\ mol= \frac{Mass}{51.9961\ g/mol}$

$Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g$

Calculation of the mass of neon as:-

Moles = $4.08\times 10^{-8}$ moles

Molar mass of neon = 20.1797 g/mol

Thus,

$1.002\ mol= \frac{Mass}{20.1797\ g/mol}$

$Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g$

6 0

2 years ago

For which property has Marvin forgotten to use an SI unit of measurement?

Nuetrik [128]

The answer to your question would be _B High Temp

8 0

2 years ago

Read 2 more answers

The burning of 80.3 g of SiH4 at constant pressure gives off 3790 kJ of heat. Calculate △H for this reaction. SiH4(g) + 2O2(g) ⟶

Trava [24]

Answer : The value of ΔH for this reaction is, -1516 kJ/mol

Explanation :

First we have to calculate the moles of $SiH_4$

$\text{Moles of }SiH_4=\frac{\text{Mass of }SiH_4}{\text{Molar mass of }SiH_4}$

$\text{Moles of }SiH_4=\frac{80.3g}{32.12g/mol}$

$\text{Moles of }SiH_4=2.5mol$

Now we have to calculate the ΔH for this reaction.

As, 2.5 mole of $SiH_4$ react to gives heat = -3790 kJ

So, 1 mole of $SiH_4$ react to gives heat = $-\frac{3790kJ}{2.5mol}$

= -1516 kJ/mol

Therefore, the value of ΔH for this reaction is, -1516 kJ/mol

7 0

2 years ago