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n200080 [17]
2 years ago
4

Chromium metal is immersed in an aqueous solution of cobalt(II) chloride.Express your answer as a chemical equation. Identify al

l of the phases in your answer. Enter noreaction if no reaction occurs.
Chemistry
1 answer:
WARRIOR [948]2 years ago
5 0

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

The chemical equation for the reaction of chromium metal and cobalt(II) chloride solution follows:

2Cr(s)+3CoCl_2(aq.)\rightarrow 2CrCl_3+3Co

As, chromium lies above in the series. So, it can easily replace cobalt from its chemical reaction.

Hence, the chemical equation is written above.

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6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021
Aleks [24]

Answer:

The total amount of Au is $ 2.0\times10^{24}

Explanation:

Given that,

Mass of 1.0 ml of Au m=4\times10^{-2}\ g

Total volume of water in oceans V=1.5\times10^{21}\ L

We need to calculate the volume in ml

Using given volume

V=1.5\times10^{21}\times1000\ mL

V=1.5\times10^{24}\ mL

We need to calculate the total mass of Au  

Using given data

1\ ml\ volume = 4\times10^{-2}\ g

1.5\times10^{24}\ ml=4\times10^{-2}\times1.5\times10^{24}

So, The total mass of Au is 6\times10^{22}\ g

The mass will be in ounce,

Mass=0.035274\times6\times10^{22}

Mass=2.12\times10^{21}\ ounce

The total amount of the Au Will be

Total\ amount=2.12\times10^{21}\times948

Total\ amount=2.0\times10^{24}

Hence, The total amount of Au is $ 2.0\times10^{24}

3 0
2 years ago
A 6.50-g sample of copper metal at 25.0 °c is heated by the addition of 84.0 j of energy. the final temperature of the copper i
anzhelika [568]
The final temperature of the copper is 59.0. The specific heat capacity of copper is 0.38 j/g -k
3 0
2 years ago
Nickel can be plated from aqueous solution according to the following half reaction. How long would it take (in min) to plate 29
andrey2020 [161]

Answer:

It take 3.5 *10² min

Explanation:

Step 1: Data given

Mass of the nickel = 29.6 grams

4.7A

Step 2: The balanced equation

Ni2+ (aq- +2e- → Ni(s)

Step 3: Calculate time

W = (ItA)/(n*F)

  ⇒ W = weight of plated metal in grams = 29.6

 ⇒ I = current in coulombs per second. = 4.7

 ⇒ t = time in seconds.

 ⇒ A = atomic weight of the metal in grams per mole. = 58.69

 ⇒ n = valence of dissolved metal in solution in equivalents per mole.  = 2

 ⇒ F = Faraday's constant in coulombs per equivalent. F = 96,485.309               coulombs/equivalent.

29.6 = (4.7 * t * 58.69)/(2*96485309)

t = 20707 seconds

t =345 minutes = 3.5 * 10² min

It take 3.5 *10² min

7 0
2 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
2 years ago
What is the balanced chemical equation for the reaction used to calculate ΔH∘f of SrCO3(s)? If fractional coefficients are requi
Pani-rosa [81]

Answer:

Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

Explanation:

The standard enthalpy of formation (ΔH°f) is the energy involved in the formation of 1  mole of a substance from its elements in their most stable states. The chemical equation for the formation of SrCO₃(s) is the following.

Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

6 0
2 years ago
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