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2 years ago

4

A circular coil with 600 turns has a radius of 15 cm. The coil is rotating about an axis perpendicular to a magnetic field of 0.

020 T. If the maximum induced emf in the coil is 1.6 V, at what angular frequency is the coil rotating?
a. 1.9 rad/s
b. 0.90 rad/s
c. 1.4 rad/sec
d. 0.60 rad/s
e. 0.30 rad/s

1 answer:

Lerok [7]2 years ago

5 0

The answer to this question is d. 0.60 rad/s

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A +5.0-μC point charge is placed at the 0 cm mark of a meter stick and a -4.0-μC charge is placed at the 50 cm mark. What is the

algol13

Answer:

1.4 *10^6 N/C

Explanation:

The electric field caused by a charge at a certain point is given by the equation:

$E = k \frac{q}{r} \^r$

where k is the Coulomb constant equal to 8.99 *10^9 Nm^2/C^2, q the charge of the particle in coulombs, r is the distance from the point to the charge in meters.

$\^r$ is the unitary vector that goes from the charge to the point. This vector will give us the direction of the Electric Field vector.

The unitary vector of the +5.0-μC charge will go to the right (+i), as the point is to the right of the charge. Then, the electric field caused by the charge will be:

$E_1 = k \frac{q}{r^2} \^r = 8.99*10^9 Nm^2/C^2 \frac{5.0 *10^{-6}C}{(0.3m - 0m)^2}(+\^i) = +0.5*10^6 N/C$

The unitary vector of the -4.0-μC charge will go to the left (-i), as the point is to the left of the charge. Then, the electric field caused by the charge will be:

$E_2 = k \frac{q}{r^2} \^r = 8.99*10^9 Nm^2/C^2 \frac{-4.0 *10^{-6}C}{(0.5m - 0.3m)^2}(-\^i) = +0.9*10^6 N/C$

The electric field at the 30 cm mark will be the addition of both electric field:

$E_{total} = E_1 +E_2 = 0.5 *10^6 N/C + 0.9*10^6 N/C = 1.4 *10^6 N/C$

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2 years ago

A sample of a gas occupies a volume of 90 mL at 298 K and a pressure of 702 mm Hg. What is the correct expression for calculatin

aleksandr82 [10.1K]

Answer:

Explanation:

Given

volume of sample $V_1=90\ mL$

Temperature $T_1=298\ K$

Pressure $P_1=702\ mm\ of\ Hg$

for different conditions

Temperature $T_2=273\ K$

Pressure $P_2=760\ mm\ of\ Hg$

suppose $V_2$ is the volume of sample

Using ideal gas equation

$PV=nRT$

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$\frac{702\times 90}{298}=\frac{760\times V_2}{273}$

$V_2=76.15\ mL$

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2 years ago

A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr

Harlamova29_29 [7]

Answer:

a) m = 3 for λ1 and m= 2 for λ2 will overlap since they have the same values

b) At what angle does this overlap occur = 34.54 degree

Explanation:

The detailed steps and appropriate formula is as shown in the attachment.

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2 years ago

g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

sdas [7]

Answer:

The vertical distance is $d = \frac{2}{k} *[mg + f]$

Explanation:

From the question we are told that

The mass of the cylinder is m

The kinetic frictional force is f

Generally from the work energy theorem

$E = P + W_f$

Here E the the energy of the spring which is increasing and this is mathematically represented as

$E = \frac{1}{2} * k * d^2$

Here k is the spring constant

P is the potential energy of the cylinder which is mathematically represented as

$P = mgd$

And

$W_f$ is the workdone by friction which is mathematically represented as

$W_f = f * d$

So

$\frac{1}{2} * k * d^2 = mgd + f * d$

=> $\frac{1}{2} * k * d^2 = d[mg + f ]$

=> $\frac{1}{2} * k * d = [mg + f ]$

=> $d = \frac{2}{k} *[mg + f]$

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2 years ago

You and your family take a trip to see your aunt who lives 100 miles away along a straight highway. The first 60 miles of the tr

Nitella [24]

Answer:

51.2 mi/h

Explanation:

Total distance, d = 100 miles

First 60 miles with speed 55 mi/h

Next 40 miles with speed 75 mi/h

Time taken for first 60 miles, t1 = 60 / 55 = 1.09 h

Time taken for 40 miles, t2 = 40 / 75 = 0.533 h

Time spent to get stuck, t3 = 20 min = 0.33 h

Total time, t = t1 + t2 + t3 = 1.09 + 0.533 + 0.33 = 1.953 h

The average speed is defined as the ratio of total distance traveled to the total time taken.

Average speed = $=\frac{100}{1.953}=51.2 mi/h$

Thus, the average speed of the journey is 51.2 mi/h.

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2 years ago