answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr [31]
2 years ago
14

During a car accident, a 125 kg driver is moving at 31 m/s and in 1.5 seconds is brought to rest by an inflating air bag. What i

s the magnitude of the change in momentum of the driver?
Physics
2 answers:
MrMuchimi2 years ago
8 0
Momentum = (mass) (speed)

The driver's initial momentum is (125 kg) (31 m/s) = 3,875 kg-m/s

At rest, his momentum is zero.

The change in his momentum is  (0 - 3,875 kg-m/s)  =  - 3,875 kg-m/s .

The average force exerted on him by the airbag is

                          (3,875 kg-m/s) / (1.5 s)

                     =        2,583.333... kg-m/s²

                     =         2,583.333... newtons   (about about 581 pounds)

That's what it takes to stop a 125 kg mass moving at 31m/s in 1.5sec.

The negative acceleration is    31/1.5 m/s² = about

                                                   =  20.333... m/s²  =  about  2.1 'G's.

If he were not wearing his seat belt and the airbag did not deploy,
then he would not be brought to rest ... at least not until he hit the
windshield at 31 m/s ... about  69.3 mph .








              
Vitek1552 [10]2 years ago
5 0

Answer: D

Explanation:

3900kg•m/s

You might be interested in
The image on the left shows the charges on a balloon after it’s been rubbed with a wool cloth. The image on the right is a piece
taurus [48]

When wool is rubbed with a balloon, the wool is left with a positive charge as electrons have travelled from the wool to the balloon which means the balloon now has a negative charge.

Now that the balloon has a negative charge, you need to know:
The tissue paper originally contains electrons and protons
The fact that the balloon has a negative charge, it will ATTRACT protons because protons are POSITIVE and electrons are NEGATIVE.
So once they are attracted, they will move closer to one another.
3 0
2 years ago
Read 2 more answers
A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?
denpristay [2]
<span><span>1.       </span>If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.</span>



6 0
2 years ago
An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
Marysya12 [62]

When air is blown into the open pipe,

L = \frac{nλ}{2}

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=\frac{2L} {n}

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ=\frac{(2)*(6)}{4} =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= \frac{c}{λ}

⇒f=\frac{344}{3}

≈115 Hz

8 0
2 years ago
A large ebony wood log, totally submerged, is rapidly floating down a flooded river. If the mass of the log is 165 kg, what is t
Sedbober [7]

Answer:

F = 1618.65[N]

Explanation:

To solve this problem we use the following equation that relates the mass, density and volume of the body to the floating force.

We know that the density of wood is equal to 750 [kg/m^3]

density = m / V

where:

m = mass = 165[kg]

V = volume [m^3]

V = m / density

V = 165 / 750

V = 0.22 [m^3]

The floating force is equal to:

F = density * g * V

F = 750*9.81*0.22

F = 1618.65[N]

3 0
2 years ago
|| Climbing ropes stretch when they catch a falling climber, thus increasing the time it takes the climber to come to rest and r
Otrada [13]

To solve this problem it is necessary to apply the concepts related to Newton's second law and the kinematic equations of movement description.

Newton's second law is defined as

F = ma

Where,

m = mass

a = acceleration

From this equation we can figure the acceleration out, then

a = \frac{F}{m}

a = \frac{11*10^3}{80}

a = 137.5m/s

From the cinematic equations of motion we know that

v_f^2-v_i^2 = 2ax

Where,

v_f =Final velocity

v_i =Initial velocity

a = acceleration

x = displacement

There is not Final velocity and the acceleration is equal to the gravity, then

v_f^2-v_i^2 = 2ax

0-v_i^2 = 2(-g)x

v_i =\sqrt{2gx}

v_i = \sqrt{2*9.8*4.8}

v_i = 9.69m/s

From the equation of motion where acceleration is equal to the velocity in function of time we have

a = \frac{v_i}{t}

t = \frac{v_i}{a}

t =\frac{9.69}{137.5}

t = 0.0705s

Therefore the time required is 0.0705s

4 0
2 years ago
Read 2 more answers
Other questions:
  • A certain 100W light bulb has an efficiency of 95%. How much thermal energy will this light bulb add to the inside of a room in
    12·1 answer
  • A bobsled is pushed with a force of 190.08 N. The sled has a mass of 28 kg. What is the acceleration of the bobsled? Report to t
    15·1 answer
  • A system delivers 1275 j of heat while the surroundings perform 855 j of work on it. calculate ∆esys in j.
    8·1 answer
  • If there is a potential difference v between the metal and the detector, what is the minimum energy emin that an electron must h
    11·1 answer
  • Find the wavelength of the ultrasonic wave emitted by a bat if it has a frequency of 4.0 * 10^4 Hz.
    14·2 answers
  • Using the superposition method, calculate the current through R5 in Figure 8-71
    14·1 answer
  • A 0.500 kg aluminum pan on a stove is used to heat 0.250 liters of water from 20.0ºC to 80.0ºC. (a) How much heatis required? Wh
    15·1 answer
  • Charlie is playing with his daughter Torrey in the snow. She sits on a sled and asks him to slide her across a flat, horizontal
    10·2 answers
  • Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
    12·1 answer
  • The small piston of a hydraulic lift has a cross-sectional of 3 00 cm2 and its large piston has a cross-sectional area of 200 cm
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!