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Naddika [18.5K]
2 years ago
14

A circular loop of wire lies flat on a level table top in a region where the magnetic field vector points straight upward. The m

agnetic field suddenly vanishes. As viewed from above, in what direction does the induced current flow in the loop of wire?An induced current flows counterclockwise in the loop of wire.An induced current flows clockwise in the loop of wire.No current is induced in the loop of wire.The direction of the induced current cannot be determined from the given information.
Physics
1 answer:
Svetlanka [38]2 years ago
3 0

Answer:

An induced current flow counterclockwise in the loop of wire

Explanation:

The magnetic field directed normally up wards and the magnetic flux directed upwards decreases suddenly.

The reduction in magnetic flux induces the EMF and current.

Magnetic field B points upward i.e. along she +z axis

B= z•k

Since the magnetic field vanishes, then, B=0

The force in field is given as

F=L( i×B)

For the magnetic field to vanish, the current has to move in opposite direction i.e. counterclockwise the loop wire.

Therefore the induced EMF and current will try to nullify this effect by producing more magnetic field directed up wards from the plane of the surface and this current have to flow in opposite or counterclockwise direction.

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Two objects have masses m and 5m, respectively. They both are placed side by side on a frictionless inclined plane and allowed t
poizon [28]

Answer:

(E) The two objects reach the bottom of the incline at the same time.

Explanation:

Given;

first object with mass, m

second object with mass, 5m

The acceleration of gravity for both object is the same = 9.8 m/s²

Since both objects have the same acceleration of gravity, and no external force due friction (frictionless inclined plane), they will reach bottom of the inclined at the time.

Thus, the acceleration due to gravity is constant for all objects regardless of their masses.

Therefore, the correct option is E;

(E) The two objects reach the bottom of the incline at the same time.

5 0
2 years ago
Juan was wearing a bright red shirt in a very dark room. What color did his shirt appear to the people with him in the room? A)
ikadub [295]
It would appear black.   

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8 0
2 years ago
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A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average
frez [133]
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
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<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
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so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
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2 years ago
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The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where sec
saveliy_v [14]

The static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta.

The given parameters;

  • <em>mass of the block, = M</em>
  • <em>coefficient of static friction in section 1, = </em>\mu_s_1<em />
  • <em>angle of inclination of the plane, = θ</em>

<em />

The normal force on the block is calculated as follows;

Fₙ = Mgcosθ

The static friction exerted on the block by the incline is calculated as follows;

F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta

Thus, the static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta

Learn more here:brainly.com/question/17237604

3 0
2 years ago
"For a first order instrument with a sensitivity of .4 mV/K and a time" constant of 25 ms, find the instrument’s response as a f
ELEN [110]

Answer:

Explanation:

Given that:

For a first order instrument with a sensitivity of .4 mV/K

constant c  = 25 ms = 25 × 10⁻³ s

The initial temperature T_1 = 273 K

The final temperature T_2 = 473 K

The initial volume = 0.4 mV/K × 273 K = 109.2 V

The final volume =  0.4 mV/K × 473 K =  189.2 V

the instrument’s response as a function of time for a sudden temperature increase can be computed as follows:

Let consider y to be the function of time i.e y(t).

So;

y(t) = 109.2  + (189.2 - 109.2)( 1 - \mathbf{e^{-t/c}})mV

y(t) = (109.2 +  80 ( 1 - \mathbf{e^{t/25\times 10^{-3}}})) mV

Plot the response y(t) as a function of time.

The plot of y(t) as a function of time can be seen in the diagram  attached below.

What are the units for y(t)?

The unit for y(t) is mV.

Find the 90% rise time for y(t90) and the error fraction,

The 90% rise time for y(t90) is as follows:

Initially 90% of 189.2 mV = 0.9 ×  189.2 mV

=  170.28 mV

170.28 mV = (109.2 +  80 ( 1 - \mathbf{e^{t/25\times 10^{-3}}})) mV

170.28 mV - 109.2 mV = 80 ( 1 - \mathbf{e^{t/25\times 10^{-3}}})) mV

61.08 mV =  80 ( 1 - \mathbf{e^{t/25\times 10^{-3}}})) mV

0.7635  mV = ( 1 - \mathbf{e^{t/25\times 10^{-3}}})) mV

t = 1.44 × 25  × 10⁻³ s

t = 0.036 s

t = 36 ms

The error fraction = \dfrac{189.2-170.28  }{189.2}

The error fraction = 0.1

The error fraction = 10%

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2 years ago
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