In order to overcome an object’s inertia (resistance to change), it must be acted upon by an unbalanced force, so the answer to the problem is letter C.
Answer:
T = g μ_s ( M+m )
78.4 N
Explanation:
When both of them move with the same acceleration , small box will not slip over the bigger one. When we apply force on the lower box, it starts moving with respect to lower box. So a frictional force arises on the lower box which helps it too to go ahead . The maximum value that this force can attain is mg μ_s . As a reaction of this force, another force acts on the lower box in opposite direction .
Net force on the lower box
= T - mg μ_s = M a ( a is the acceleration created by net force in M )
Considering force on the upper box
mg μ_s = ma
a = g μ_s
Put this value of a in the equation above
T - m gμ_s = M g μ_s
T = mg μ_s + M g μ_s
= g μ_s ( M+m )
2 )
Largest tension required
T = 9.8 x .50 x ( 10+6 )
= 78.4 N
Answer:
Explanation:
Position of charge q₁ is (0,0)
Position of charge q₂ is (x₁,0)
So, the electric potential energy between the charges is given by :
Now the position of charge q₂ has been changes from (x₁,0) to (x₂,y₂). Now, electric potential energy between the charges is :
We know form the work energy theorem that, the change in potential energy is equal to the work done. Mathematically, it is given by :
Hence, the work done by the electrostatic force on the moving point charge is 
. Hence, this is the required solution.
Answer:
When she adds more washers to the meter, the magnitude of force that is shown on the force meter increases.
Explanation:
The force that the washers exert on the force meter is actually the weight of the washers. Weight is actually a force with gravitation acceleration.
F = W = mg
Where g is gravitational acceleration and its value is 9.81 m/s² and m is the mass of any object. As she adds more washers to the meter so the total mass of the washers increases. As the mass of the washers increases, magnitude of the force (Weight) shown on the force meter increases.
There is no picture given so I can't be really sure what color of the cable you're referring to. However, the only relationship I can think of when the power and the current is given would be: P=IV or P = I²R, where P is power, I is current, V is voltage and R is resistance. Solving both equations:
120 W = (24 A)(Voltage)
Voltage = 5 V
120 W = (24 A)²(R)
R = 0.2083 Ω
So, i think the cable would have specification of 5 Volts and 0.2083 ohms.
