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ivann1987 [24]
2 years ago
3

Ben and Sam were conducting experiments on physical and chemical changes in science class. First they added some salt to water a

nd stirred it up until the salt dissolved. "That's a physical change" Ben said. "And that's a solution which is a mixture", added Sam. Next they added an anti-acid tablet to some water. The water began to fizz and bubble. The beaker got cooler. "That's a physical change too," Ben noted. "No, it's not," responded Sam. Who is correct and where should the contents of the beaker be placed in the Venn diagram?
A) Sam is correct. It is not a physical change and it should be placed in A
B) Sam is correct. It is a chemical change and the contents should be in D. for compound.
C) Ben is correct. It is a physical change and it is a solution, placing it in B. as a mixture.
D) They are both correct. It is a mixture and a compound and the contents should be placed in C.
Chemistry
2 answers:
NemiM [27]2 years ago
7 0

Answer: it’s A

Explanation:

I DID THE USA TEST PREP LEAVE SOME STARS IF CORRECT .

marta [7]2 years ago
6 0

Answer:A

Explanation:

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In which orbitals would the valence electrons for carbon <br> c. be placed?
katrin2010 [14]

Answer: 2s and 2p

Explanation: Carbon is an element with atomic number of 6 and thus contains 6 electrons. The electrons are filled in order of increasing energies and follows Afbau's rule.The electrons are singly filled first in each orbital having same spin, then only pairing occurs. This rule was known as Hund's Rule.

The valence electrons are the electrons which are present in last shell. Thus valence electrons are 4, two in s and 2 in p orbitals.

C: 6:1s^22s^22p_x^12p_y^1


8 0
2 years ago
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Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
AnnyKZ [126]
1) Chemical equation

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) molar ratios

1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3)2 : 2 mol Ag

3) Convert 12. 83 * 10^23 atoms of Cu in moles

12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Use the proportions

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) Use the atomic mass of silver to convert 4.262 mol in grams

mass = number of moles * atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

Answer: 459.9 g
5 0
2 years ago
How many hydrogen bonds can CH2O make to water
VladimirAG [237]
Hydrogen bonds are not like covalent bonds. They are nowhere near as strong and you can't think of them in terms of a definite number like a valence. Polar molecules interact with each other and hydrogen bonds are an example of this where the interaction is especially strong. In your example you could represent it like this: 

<span>H2C=O---------H-OH </span>

<span>But you should remember that the H2O molecule will be exchanging constantly with others in the solvation shell of the formaldehyde molecule and these in turn will be exchanging with other H2O molecules in the bulk solution. </span>

<span>Formaldehyde in aqueous solution is in equilibrium with its hydrate. </span>

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2 years ago
What is the difference between calorie and Calorie?
Blababa [14]

What is the difference between calories and kilocalories? The "calorie" we refer to in food is actually kilocalorie. One (1) kilocalorie is the same as one (1) Calorie (upper case C). A kilocalorie is the amount of heat required to raise the temperature of 1 kilogram of water one degree Celsius.

5 0
2 years ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
VLD [36.1K]

Answer:- 64015 J

Solution: There is 4250 mL of water in the calorimeter at 22.55 degree C.

density of water is 1 g per mL.

So, the mass of water = 4250mL(\frac{1g}{1mL})  = 4250 g

Final temperature of water after adding the hot copper bar to it is 26.15 degree C.

So, \Delta T for water = 26.15 - 22.55 = 3.60 degree C

Specific heat for water is 4.184 \frac{J}{g.^0C}

The heat gained by water is calculated by using the formula:

q=mc\Delta T

where, q is the heat energy, m is mass and c is specific heat.

Let's plug in the values in the formula and do the calculations:

q=4250g*\frac{4.184J}{g.^0C}*3.60^0C

q = 64015 J

So, 64015 J of heat is gained by the water.



5 0
2 years ago
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