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natka813 [3]
2 years ago
14

Jack researched J.J. Thomson’s experiments. Read Jack’s summary below and find the error.

Chemistry
1 answer:
WINSTONCH [101]2 years ago
8 0

Answer:

D. Error is in sentence 1. The beam was a cathode ray.

Explanation:

Legit just looked up his experiments and it said right off the bat he studied cathode rays not gamma.

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A chef is serving a lunch special with 1 sandwich and 2 corn cobs per plate. If there are 5 sandwiches and 14 corn cobs, what is
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5 plates is the highest amount that can be served

There’s only 5 sandwiches so 7 is automatically ruled out, there’s 14 corn cobs and 5 sandwiches only need 10 so it works out
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2 years ago
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X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc
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Explanation:

Given: \lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}

Its frequency \nu is defined as

\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}

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1 year ago
A scientist stores a very large number of particles in a container in order to determine the number of particles the scientist m
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2 years ago
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Consider the following balanced equation: Fe + 2Ag+ Fe2+ + 2Ag Which statement is true?
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I’m pretty sure it’s d
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2 years ago
Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 26.34 mL sample of 0.0100 M K
Dmitry [639]

Answer:

0.1 M

Explanation:

The overall balanced reaction equation for the process is;

IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)

Generally, we must note that;

1 mol of IO3^- require 6 moles of S2O3^2-

Thus;

n (iodate) = n(thiosulfate)/6

C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6

Concentration of iodate C(iodate)= 0.0100 M

Volume of iodate= V(iodate)= 26.34 ml

Concentration of thiosulphate= C(thiosulfate)= the unknown

Volume of thiosulphate=V(thiosulfate)= 15.51 ml

Hence;

C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)

0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M

5 0
2 years ago
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