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stira [4]
2 years ago
14

A fair ground ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follo

w has an 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?
Physics
1 answer:
Licemer1 [7]2 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution:

 <span>centripetal accel = 1.5*g 
ω²r = 1.5*9.8m/s² 
ω² * 8m = 14.7 m/s² 
ω = 1.36 rad/s * 1rev/2πrads * 60s/min = 12.9 rpm</span>

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While traveling from Boston to Hartford, Person A drives at a constant speed of 55 mph for the entire trip. Person B drives at 6
Ne4ueva [31]

Answer:

B will take 1.034 times the time of A from Boston to Hartford.

Explanation:

Let the distance from Boston to Hartford be S.

Person A drives at a constant speed of 55 mph for the entire trip,

Time taken by person A

             t_A=\frac{S}{55}

Person B drives at 65 mph for half the distance and then drives 45 mph for the second half of the distance.

Time taken by person B

            t_B=\frac{\frac{S}{2}}{65}+\frac{\frac{S}{2}}{45}=\frac{S}{130}+\frac{S}{90}=\frac{220S}{130\times 90}=\frac{11S}{585}

Ratio of time of arrival of B to A

                      \frac{t_B}{t_A}=\frac{\frac{11S}{585}}{\frac{S}{55}}=\frac{121}{117}=1.034

B will take 1.034 times the time of A from Boston to Hartford.

8 0
2 years ago
Two identical carts travel at the same speed toward each other, and then a collision occurs. The graphs show the momentum of eac
madam [21]

Explanation :

The interaction between two objects is termed as the collision. The collision can be of two types i.e. elastic collision and inelastic collision.

In this case, two identical carts travel at the same speed toward each other, and then a collision occurs. In an inelastic collision, the momentum before and after the collision remains the same but its kinetic energy gets lost.

After the collision, both the object sticks over each other and moves with one velocity.

Out of the given graph, the graph that shows a perfectly inelastic collision is attached. It shows that after the collision both the carts move with the same velocity.

5 0
2 years ago
4. In a closed system consisting of a cannon and a cannonball, the kinetic energy of a cannon is 72,000 J. If the cannonball is
FromTheMoon [43]

Answer:

D an B

Explanation:

3 0
2 years ago
Read 2 more answers
Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. Wha
MArishka [77]

Answer:

P = 1.64 \times 10^4 Watt

Explanation:

Here we know that the glider is accelerated uniformly from rest to final speed of 25.7 m/s in total distance of d = 46.9 m

so we will have

v_f = 25.7 m/s

v_i = 0

d = 46.9

so for uniformly accelerated motion we have

d = \frac{v_f + v_i}{2} t

46.9 = \frac{25.7 + 0}{2}t

t = 3.65 s

now we will find the total work done given as change in kinetic energy

W = \frac{1}{2}mv^2

W = \frac{1}{2}(181)(25.7^2)

W = 5.97 \times 10^4 J

now power is given as

P = \frac{W}{t}

P = \frac{5.97 \times 10^4}{3.65}

P = 1.64 \times 10^4 Watt

6 0
2 years ago
carbon-14 has a half-life of approximately 5,700 years. a fossil shell contain 25% of the original amount of its carbon-14. appr
denis23 [38]

The half-life equation m=m_{0} (\frac{1}{2})^n in which <em>n </em>is equal to the number of half-lives that have passed can be altered to solve for <em>n.</em>

<em>n = \frac{log(\frac{m}{m_{0}} )}{log(\frac{1}{2})}</em>

<em>\frac{log(\frac{.25}{1} )}{log(\frac{1}{2})} = 2</em>

Then, the number of half-lives that passed can be multiplied by the length of a half-life to find the total time.

<em>2 * 5700 =  </em>11400 yr

3 0
2 years ago
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