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crimeas [40]
2 years ago
15

Three sections of the periodic table are labeled A, B, and C in the image below.

Chemistry
1 answer:
OLga [1]2 years ago
3 0

Answer:

Choice number two: this element is malleable and ductile.

Explanation:

A modern periodic table can be split into three sections:

(from left to right)

  • Metals,
  • Metalloids, and
  • Nonmetals.

Based on the descriptions, section A likely refers to the metals. Section B likely refers to metalloids. Section C likely refers to nonmetals.

Metals are malleable and ductile. They are good conductors of electricity.

The reason is that in a metal, the valence electrons do not belong to some specific atom. Rather, the metal cations share these electrons. The electrons are free to move around the metal and conduct electricity.

Ionic compounds like table salt are brittle. The reason is that when an ionic compound is deshaped, ions of the same charge come directly into contact with each other. That creates repulsion and cracks the crystal. In contrast, the metal cations in a metal won't come into contact with each other. Electrons would rapidly fill the gap between these cations, so the metal won't crack. That's why unlike ionic compounds, metals are malleable and ductile.

The melting points of metals can vary significantly. Indeed, the mercury (\rm Hg, a metal) is a liquid at room temperature. In contrast, tungsten (\rm W, also a metal) won't melt until it is heated to over \rm 3000\, ^\circ C.

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For a solar eclipse to occur which of the following alignments is necessary? A. The moon is located along a straight line betwee
svlad2 [7]

A. I'm pretty sure, could be C though..

8 0
2 years ago
choose the reaction that illustrates delta H *f for Ca(NO3)2.(A) Ca (s) + N2 (g) + 3O2 ---> Ca(NO3)2 (s)(B) Ca2 (aq) + 2 NO3-
kompoz [17]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Standard enthalpy of formation is the change in enthalpy of  one mole of a substance present at the standard state that is 1 atm of pressure and 298 K of temperature. The substance is formed from its pure elements under the same conditions.

We are given a chemical compound having chemical formula Ca(NO_3)_2

This compound is formed by the combination of calcium, nitrogen and oxygen elements.

The chemical equation for the formation of Ca(NO_3)_2 from the components in their standard states follows:

Ca+N_2+3O_2\rightarrow Ca(NO_3)_3

Hence, the correct answer is Option A.

3 0
2 years ago
Consider the dissolution of MnS in water (Ksp = 3.0 × 10–14). MnS(s) + H2O(l) Mn2+(aq) + HS–(aq) + OH–(aq) How is the solubility
Mademuasel [1]

Answer:

The solubility of MnS will decrease on addition of KOH solution.

Explanation:

As per the equation given:

MnS(s)+H_{2}O(l) -->Mn^{+2}(aq)+HS^{-}(aq)+OH^{-}(aq)

On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.

Now when the we are adding aqueous KOH solution, it will dissociate as:

KOH(aq)--->K^{+}(aq)+OH^{-}(aq)

Thus it will further furnish more hydroxide ion,

This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.

Thus the solubility of MnS will decrease on addition of KOH solution.

7 0
2 years ago
Nuclear power plants produce energy using fission. One common fuel, uranium-235, produces energy through the fission reaction 23
Vikentia [17]

Answer:

mass of U-235  = 15.9 g (3 sig. figures)

Explanation:

1 atom can produce -------------------------> 3.20 x 10^-11 J energy

x atoms can produce ----------------------> 1.30 x 10^12 J energy

x = 1.30 x 10^12 / 3.20 x 10^-11

x = 4.06 x 10^22 atoms

1 mol ----------------------> 6.023 x 10^23 atoms

y mol ----------------------> 4.06 x 10^22 atoms

y = 0.0675 moles

mass of U-235 = 0.0675 x 235 = 15.8625

mass of U-235  = 15.9 g (3 sig. figures)

7 0
2 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
3 0
2 years ago
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