Answer:
1.98 atm
Explanation:
Given that:
Temperature = 28.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
n = 1
V = 0.500 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
P × 0.500 L = 1 ×0.0821 L atm/ K mol × 301.15 K
⇒P (ideal) = 49.45 atm
Using Van der Waal's equation
R = 0.0821 L atm/ K mol
Where, a and b are constants.
For Ar, given that:
So, a = 1.345 atm L² / mol²
b = 0.03219 L / mol
So,


⇒P (real) = 47.47 atm
Difference in pressure = 49.45 atm - 47.47 atm = 1.98 atm
Answer:2.53*10^-10F
Explanation:
C=£o£r*A/d
Where £ is the permitivity of a constant
£o= 8.85*10^-12f/m
£r=6.3
A=150mm^2=0.015m^2
d=3.3mm= 0.0033m
C=8.85*10^-12*6.3*0.015/0.0033
C=8.85*6.3*10^-12*0.015/0.0033
C=55.755*0.015^-12/0.003
C=8.36/3.3*10^-13+3
C=2.53*10^-10F
It means you can do 550 Newton Meters of work every second. Power is the rate of doing work, I hope this helps
You did not include the quesetion, but I can help you to understand the problem and how to find the relevant information.
1) The angle of 13° with which the shark ascends meets this:
Vertical ascending velocity = 0.85m/s * sin(13°)
Horizontal velocity = 0.85m/s * cos(13°)
2) The length swan by the shark ascending meets this
Vertical ascending length = 50 m
Horizontal length, y:

From that y = 50 * tan(13°)
=> y = 11.54 m.
3) Conclusions:
1) The shark run 50 m vertically upward and 11.54 m horizontally.
2) The length of the path run by the shark may be calculated using Pythagoras' theorem:
hypotenuse^2 = (50m)^2 + (11.54m)^2 = 2633.25m^2
hypotenuse = 51.35m
So, the shark swan 51.35 m to reach the surface.
Answer:
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