All categories

2 years ago

an ice skater is moving at a speed of 2 mi/hr when she slams into a wall 0.05 hours later. what is her acceleration?

Physics

2 answers:

Firdavs [7]2 years ago

7 0

Answer:

0.00497m/s²

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,

Acceleration = change in velocity/time

Given velocity = 2miles/hour

Converting mi/hr to m/s,

1mi/hr = 0.447m/s

2mi/hr = 2×0.447

= 0.894m/s

Time taken to slam into a wall = 0.05hours

Converting this to seconds will give;

0.05×60×60

= 180seconds

Acceleration = 0.894/180

Acceleration = 0.00497m/s²

nikklg [1K]2 years ago

6 0

$v_{f} = v_{0}+at$
at $v_{f}=0$
$v_{0}=at$
$-2=0.05a$
$a= \frac{-2}{0.05} =-40mi/hr$

Hope this helps.

You might be interested in

To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V

aleksley [76]

Answer:

The maximum energy stored in the combination is 0.0466Joules

Explanation:

The question is incomplete. Here is the complete question.

Three capacitors C1-11.7 μF, C2 21.0 μF, and C3 = 28.8 μF are connected in series. To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V. Determine the maximum energy stored in the series combination.

Energy stored in a capacitor is expressed as E = 1/2CtV² where

Ct is the total effective capacitance

V is the supply voltage

Since the capacitors are connected in series.

1/Ct = 1/C1+1/C2+1/C3

Given C1 = 11.7 μF, C2 = 21.0 μF, and C3 = 28.8 μF

1/Ct = 1/11.7 + 1/21.0 + 1/28.8

1/Ct = 0.0855+0.0476+0.0347

1/Ct = 0.1678

Ct = 1/0.1678

Ct = 5.96μF

Ct = 5.96×10^-6F

Since V = 125V

E = 1/2(5.96×10^-6)(125)²

E = 0.0466Joules

8 0

2 years ago

Assume you are driving 20 mph on a straight road. Also, assume that at a speed of 20 miles per hour, it takes 100 feet to stop.

Viefleur [7K]

Answer:900 feet

Explanation:

Given

Velocity $\left ( V_1\right )=20 mph\approx 29.334 ft/s$

it take 100 feet to stop

Using Equation of motion

$v^2-u^2=2as$

where

v,u=Final and initial velocity

a=acceleration

s=distance moved

$0-\left ( 29.334\right )^2=2\left (-a\right )\left ( 100\right )$

$a=\frac{29.334^2}{2\times 100}=4.302 ft/s^2$

When velocity is 60 mph $\approx 88.002 ft/s$

$v^2-u^2=2as$

$0-\left ( 88.002\right )^2=2\left ( -4.302\right )\left ( s\right )$

s=900.08 feet

8 0

2 years ago

Read 2 more answers

Consider two circular metal wire loops each carrying the same current I as shown below. In what r... Consider two circular metal

NeX [460]

Answer:

1) The magnetic field outside the loop is zero.

In region III the magnetic fields due to the two wire loops point in the opposite direction andhence cancel each other. Therefore the magnetic field is zero in region I, III and V

The diagram is attached