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V125BC [204]
2 years ago
6

A loop is placed in a region where the magnetic field is changing. At t = 0 s the magnetic field is 1 T directed into the page.

Over a period of 2 s, the field changes uniformly to 1 T directed out of the page.
Which of the following describes the direction, clockwise (CW) or counterclockwise (CCW), of the induced EMF in the loop?
Physics
1 answer:
Trava [24]2 years ago
4 0

Answer:

Clockwise

Explanation:

According to Faraday-Newmann-Lenz's law, when there is a change in magnetic flux linkage through a coil, an emf is induced in the coil, and it is given by the equation

\epsilon=-\frac{Nd\Phi}{dt}

where

N is the number of turns in the coil

\frac{d\Phi}{dt} is the rate of change of magnetic flux in the coil

The negative sign in the formula indicates the direction of the induced emf, which is such that it opposes the direction of change in magnetic flux that originated the emf.

In this problem:

- At the beginning, the magnetic field is 1 T directed into the page

- Then, this magnetic field changes uniformly to 1 T directed out of the page (opposite direction)

We split the problem into two parts:

- In the first part, the strength of the magnetic field changes uniformly from 1 T to 0. This means that the magnetic flux through the coil is decreasing: therefore, the induced emf must be such that it produces a magnetic field that try to add to the original field. Using the right hand rule (thumb in the direction of the current in the loop and other fingers "wrapped" to give the direction of the field), we see that in order to produce a magnetic field into the page, the current must be clockwise.

- In the second part, the strength of the magnetic field changes uniformly from 0 T to 1 T, but in the direction out of the page. This means that the magnetic flux through the coil is increasing: therefore, the induced emf must be such that it produces a magnetic field that try to subtract to the original field, therefore the new produced field must be into the page (opposite direction to the external field).. Using the right hand rule again, we see that in order to produce a magnetic field into the page, the current must be clockwise again.

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A 50-kg person stands 1.5 m away from one end of a uniform 6.0-m-long scaffold of mass 70.0 kg.
babymother [125]

Answer

given,

mass of the person, m = 50 Kg

length of scaffold = 6 m

mass of scaffold, M= 70 Kg

distance of person standing from one end = 1.5 m

Tension in the vertical rope = ?

now equating all the vertical forces acting in the system.

T₁ + T₂ = m g + M g

T₁ + T₂ = 50 x 9.8  + 70 x 9.8

T₁ + T₂ = 1176...........(1)

system is equilibrium so, the moment along the system will also be zero.

taking moment about rope with tension T₂.

now,

T₁ x 6 - mg x (6-1.5) - M g x 3 = 0

'3 m' is used because the weight of the scaffold pass through center of gravity.

6 T₁ = 50 x 9.8 x 4.5 + 70 x 9.8 x 3

6 T₁ = 4263

    T₁ = 710.5 N

from equation (1)

T₂ = 1176 - 710.5

 T₂ = 465.5 N

hence, T₁ = 710.5 N and T₂ = 465.5 N

4 0
2 years ago
the temperature of a 2.0-kg increases by 5*c when 2,000 J of thermal energy are added to the block. What is the specific heat of
nata0808 [166]
To calculate the specific heat capacity of an object or substance, we can use the formula

c = E / m△T

Where
c as the specific heat capacity,
E as the energy applied (assume no heat loss to surroundings),
m as mass and
△T as the energy change.

Now just substitute the numbers given into the equation.

c = 2000 / 2 x 5
c = 2000/ 10
c = 200

Therefore we can conclude that the specific heat capacity of the block is 200 Jkg^-1°C^-1
3 0
2 years ago
Planetary orbits... are spaced more closely together as they get further from the Sun. are evenly spaced throughout the solar sy
BaLLatris [955]

Answer:

E) are almost circular, with low eccentricities.

Explanation:

Kepler's laws establish that:

All the planets revolve around the Sun in an elliptic orbit, with the Sun in one of the focus (Kepler's first law).

A planet describes equal areas in equal times (Kepler's second law).

The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

T^{2} = a^{3}

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

Therefore, option A and B can not be true.

In the celestial sphere, the path that the Sun moves in a period of a year is called ecliptic, and planets pass very closely to that path.  

4 0
2 years ago
Honeybees can see light in the ________ range of the electromagnetic spectrum.
konstantin123 [22]
Humans can see wavelengths in the visible part of the electromagnetic spectrum. That is the range of approximately 400 - 700 nm. Honeybees can see visible light and about 100 nm more in the ultraviolet part of the electromagnetic spectrum. That is approximately 300 - 700 nm. 
4 0
2 years ago
A stranded soldier shoots a signal flare into the air to attract the attention of a nearby plane. The flare has an initial verti
Ipatiy [6.2K]

Answer:

Explanation:

h = ut - 16 t² = ut - 1/2 x32 t² = ut - 1/2 g t² , g = acceleration  = - 32 ft / s²

1) v² = u² - 2 g h , v = 0 so

h = u² / 2g = 1500² / 2 x 32 = 35156.25 ft

2) v = u - gt

t = u / g = 1500 / 32 = 46.875 s

3) It will hit the ground after 2 x 46.875 = 93.75 s

4 ) time to reach 30000 ft height  t is given by

h = ut - 16 t²

30000 = 1500t - 16t²

16t²-1500t + 30000 = 0

t = 28.92 s  and 64.82 s

Time required to travel 50000 by plane

= 50000/880 = 56.82 . There is no match of timing so plane will not hit it.

8 0
2 years ago
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