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vredina [299]
2 years ago
13

If The dimensions of a brick that weighs 25N are 0.19m x 0.07m x 0.095m. What pressure does the brick exert on the ground if it

is resting on its largest face?
Physics
1 answer:
valina [46]2 years ago
5 0
1 newton per square meter = 1 pascal of pressure.

The largest face of the brick is (0.19 x 0.095) = .01805 square meter

25N/0.01805 = 1,385 newtons per square meter = 1,385 pascal  = 1.385 kPa
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The image shows the displacement of a motorboat. The data table shows the magnitudes of the components of each displacement vect
Diano4ka-milaya [45]
Rx= 3.5 km

Ry= 2.9 km
4 0
2 years ago
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Consider a force of 750 n (roughly the weight of an adult human). over what area (in cm2) would this force need to be applied in
polet [3.4K]
p = \frac{f}{a}
P=25x10^6 andF=750.So plug in everything to solve for A. which is 3x10^-5m^2 OR 0.3mm^2
7 0
2 years ago
A convex mirror with a focal length of 0.25 m forms a 0.080 m tall image of an automobile at a distance of 0.24 m behind the mir
Semmy [17]

Answer:

The distance and height of the object  is 6 m and 2 m.

The image is virtual and upright.

Explanation:

Given that,

Focal length = 0.25 m

Length of image = 0.080 m

Image distance = 0.24 m

We need to calculate the distance of the object

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{0.24}=\dfrac{1}{0.25}+\dfrac{1}{u}

\dfrac{1}{u}=\dfrac{1}{0.24}-\dfrac{1}{0.25}

\dfrac{1}{u}=\dfrac{1}{6}

u=6\ m

We need to calculate the magnification

Using formula of magnification

m=-\dfrac{v}{u}

Put the value into the formula

m=-\dfrac{0.24}{-6}

m=0.04

We need to calculate the height of the object

Using formula of magnification

m=\dfrac{h'}{h}

h=\dfrac{0.080}{0.04}

h=2\ m

A convex mirror produce a virtual and upright image behind the mirror.

Hence, The distance and height of the object  is 6 m and 2 m.

The image is virtual and upright.

6 0
2 years ago
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Which of the following statements is correct? Which of the following statements is correct? The more a muscle shortens, the more
NeX [460]

The correct answer are

a)  "The number of muscle fibers best determines how powerful a muscle will be"

b) "The more a muscle shortens, the more power it generates."

Reason :

Muscle fiber in longitudinal directions generate more power

Multipennate muscles do not produce much power because the tendon branches within muscle .



4 0
2 years ago
A 0.20-kg object attached to the end of a string swings in a vertical circle (radius = 80 cm). at the top of the circle the spee
gayaneshka [121]

Answer:

Tension in the string at this position: 3.1 N.

Explanation:

Convert the radius of the circle to meters:

r = 80\;\text{cm} = 0.80\;\text{m}.

What's the net force on the object?

The object is in a circular motion. As a result,

\displaystyle \Sigma F = \frac{m\cdot v^{2}}{r},

where

  • \Sigma F is the net force on the object,
  • m is the mass of the object,
  • v is the velocity of the object, and
  • r is the radius of the circular motion.

For this object,

\displaystyle \Sigma F = \frac{0.20\times {4.5}^{2}}{0.80} = 5.0625\;\text{N}.

The output unit of net force should be standard if the unit for mass, velocity, and radius are all standard. The net force shall always point towards the center. In this case the net force points downwards.

What are the forces on this object?

There are two forces on the object at this moment:

  • Weight, W, which points downwards. W = m\cdot g = 0.20\times 9.81 = 1.962\;\text{N}.
  • Tension, T, which also points downwards. The size of the tension force needs to be found.

What's the size of the tension force?

Gravity and tension points in the same direction. The size of their resultant force is the sum of the two forces. In other words,

\Sigma F = T + W.

T = \Sigma F - W = 5.0625 - 1.962 = 3.1.

All three values in this question are given with two sig. fig. Round the value of T to the same number of significant figures.

4 0
2 years ago
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