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2 years ago

What is the de Broglie wavelength of a bullet of mass 0.075 kg traveling at 350 m/s? Planck's Constant is 6.63 × 10−34 J⋅s.

Physics

1 answer:

jasenka [17]2 years ago

3 0

Answer:

De Broglie wavelength of the bullet is given as

$\lambda = 2.5 \times 10^{-35} m$

Explanation:

As per De Broglie hypothesis we know that the wavelength of De Broglie waves is the ratio of Plank's constant and momentum of the particle

here we know that the bullet mass is

m = 0.075 kg

speed of the bullet is given as

v = 350 m/s

Now we have

$P = (0.075)(350)$

$P = 26.25 kg m/s$

Now we know that

$\lambda = \frac{h}{P}$

$\lambda = \frac{6.63 \times 10^{-34}}{26.25}$

$\lambda = 2.5 \times 10^{-35} m$

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