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aev [14]
2 years ago
4

Summarize: in general, how can you determine the mass number of the daughter product after alpha decay has taken place? How can

you determine the atomic number?
Physics
1 answer:
shtirl [24]2 years ago
4 0
An alpha particle is a helium nucleus ... a bundle of
two protons and two neutrons.

So ...

After an atom expels one alpha particle, if nothing else happens
to the nucleus, its new atomic mass is 4 less than it was originally,
and its atomic number is 2 less than it was originally ... it's now an
atom of a different element.
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What is the x component of (+3m)ι^ And (+3m/s) i^?
expeople1 [14]
The "i" component of a vector is in the x-direction. Therefore, the x-component is 3 m/s.
4 0
2 years ago
You need to design a clock that will oscillate at 10 MHz and will spend 75% of each cycle in the high state. You will be using a
Svetllana [295]

Answer:

Hello your question has some missing parts and the required diagram attached below is the missing part and the diagram

Digital circuits require actions to take place at precise times, so they are controlled by a clock that generates a steady sequence of rectangular voltage pulses. One of the most widely

used integrated circuits for creating clock pulses is called a 555 timer.  shows how the timer’s output pulses, oscillating between 0 V and 5 V, are controlled with two resistors and a capacitor. The circuit manufacturer tells users that TH, the time the clock output spends in the high (5V) state, is TH =(R1 + R2)*C*ln(2). Similarly, the time spent in the low (0 V) state is TL = R2*C*ln(2). Design a clock that will oscillate at 10 MHz and will spend 75% of each cycle in the high state. You will be using a 500 pF capacitor. What values do you need to specify for R1 and R2?

ANSWER : R1 = 144.3Ω,   R2 =  72.2 Ω

Explanation:

Frequency = 10 MHz

Time period = 1 / F =  0.1 <em>u </em>s

Duty cycle = 75% = 0.75

Duty cycle can be represented as :   Ton / T

Also: Ton = Th = 0.75 * 0.1 <em>u </em>s  = 75 <em>n</em> s

TL = T - Th = 100 <em>n</em>s - 75 <em>n</em> s = 25 <em>n</em> s

To find the value of R2 we use the equation for  time spent in the low (0 V) state

TL = R2*C*ln(2)

hence R2 = TL / ( C * In 2 )

c = 500 pF

Hence R2 = 25 / ( 500 pF * 0.693 )  = 72.2 Ω

To find the value of R1 we use the equation for the time the clock output spends in the high (5V) state,

Th = (R1 + R2)*C*ln(2)

  from the equation make R1 the subject of the formula

R1 =  (Th - ( R2 * C * In2 )) / (C * In 2)

R1 = ( 75 ns - ( 72.2 * 500 pF * 0.693)) / ( 500 pF * 0.693 )

R1 = ( 75 ns  - ( 25 ns ) / 500 pf * 0.693

     = 144.3Ω

8 0
2 years ago
The heat capacity of object B is twice that of object A. Initially A is at 300 K and B at 450 K. They are placed in thermal cont
ivann1987 [24]

Answer:

The final temperature of both objects is 400 K

Explanation:

The quantity of heat transferred per unit mass is given by;

Q = cΔT

where;

c is the specific heat capacity

ΔT is the change in temperature

The heat transferred by the  object A per unit mass is given by;

Q(A) = caΔT

where;

ca is the specific heat capacity of object A

The heat transferred by the  object B per unit mass is given by;

Q(B) = cbΔT

where;

cb is the specific heat capacity of object B

The heat lost by object B is equal to heat gained by object A

Q(A) = -Q(B)

But heat capacity of object B is twice that of object A

The final temperature of the two objects is given by

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}

But heat capacity of object B is twice that of object A

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K

Therefore, the final temperature of both objects is 400 K.

4 0
2 years ago
Which equation could be rearranged to calculate the frequency of a wave?
777dan777 [17]

Answer:

wavelength = speed/frequency

Explanation:

Required

Determine which of the options can be used to calculate frequency

The relationship between wavelength, speed and frequency is as follows;

Frequency = \frac{Wave\ Speed}{Wave\ Length} ---- Equation 1

When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does

Checking option (3)

Wave\ Length = \frac{Speed}{Frequency}

Multiply both sides by Frequency

Wave\ Length * Frequency = \frac{Speed}{Frequency} * Frequency

Wave\ Length * Frequency = Speed

Divide both sides by Wave Length

\frac{Wave\ Length * Frequency}{Wave\ Length} = \frac{Speed}{Wave\ Length }

Frequency = \frac{Speed}{Wave\ Length } --- Equation 2

<em>Comparing equation 1 and 2; both equations are the same.</em>

<em>Hence, option (3) answers the question</em>

7 0
2 years ago
A soccer player runs up behind a 0.450-kg soccer ball traveling at 3.20 m/s and kicks it in the same direction as it is moving,
NISA [10]

To develop this problem it is necessary to use the concepts related to Impulse.

The impulse is defined as the change in velocity at the rate of mass, that is

L = m\Delta V,

Where,

m = Mass

\Delta V = Change in Velocity

This change in velocity can be expressed as,

L = m(v_2-v_1)

L = 0.45*(12.8 - 3.2)

L = 0.45*9.6

L= 4.32 Kg.m/s

Therefore the magnitude of the impulse is 4.32 Kg.m/s

7 0
2 years ago
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