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Gre4nikov [31]
2 years ago
6

Which equation could be rearranged to calculate the frequency of a wave?

Physics
1 answer:
777dan777 [17]2 years ago
7 0

Answer:

wavelength = speed/frequency

Explanation:

Required

Determine which of the options can be used to calculate frequency

The relationship between wavelength, speed and frequency is as follows;

Frequency = \frac{Wave\ Speed}{Wave\ Length} ---- Equation 1

When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does

Checking option (3)

Wave\ Length = \frac{Speed}{Frequency}

Multiply both sides by Frequency

Wave\ Length * Frequency = \frac{Speed}{Frequency} * Frequency

Wave\ Length * Frequency = Speed

Divide both sides by Wave Length

\frac{Wave\ Length * Frequency}{Wave\ Length} = \frac{Speed}{Wave\ Length }

Frequency = \frac{Speed}{Wave\ Length } --- Equation 2

<em>Comparing equation 1 and 2; both equations are the same.</em>

<em>Hence, option (3) answers the question</em>

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An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m
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2 years ago
A brick of mass 2 kg is dropped from a rest position 5 m above the ground. what is its velocity at a height of 3 m above the gro
Rina8888 [55]
We can solve the problem by using the law of conservation of energy.

Using the ground as reference point, the mechanical energy of the brick when it is at 5 m from the ground is just potential energy (because the brick is initially at rest, so it doesn't have kinetic energy):
E= U = mgh=(2 kg)((9.81 m/s^2)(5 m)=98.1 J

when the brick is at h'=3 m from the ground, its mechanical energy is now sum of kinetic energy and potential energy:
E= K+U= \frac{1}{2} mv^2 + mgh'

where v is the velocity of the brick. Since E is conserved, it must be equal to the initial energy (98.1 J), so we can solve this equation to find v:
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8 0
2 years ago
A steel rod with a length of l = 1.55 m and a cross section of A = 4.45 cm2 is held fixed at the end points of the rod. What is
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To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

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Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

F = 38526.1N

Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

7 0
2 years ago
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