The first step in the reaction is the double bond of the Alkene going after the H of HBr. This protonates the Alkene via Markovnikov's rule, and forms a carbocation. The stability of this carbocation dictates the rate of the reaction.
<span>So to solve your problem, protonate all your Alkenes following Markovnikov's rule, and then compare the relative stability of your resulting carbocations. Tertiary is more stable than secondary, so an Alkene that produces a tertiary carbocation reacts faster than an Alkene that produces a secondary carbocation.
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Answer:
I.A thiol containing reagent and Heating(gentle)
II. Disulfide bond Breaker for Keratin
III. curling the hair physically
IV.A good oxidizing agent application
V. Disulfide bonds reformer for keratin to hold the shape
Explanation:
The hair is mostly made of Keratin which is a structural proteins with about 15% cysteine
In order to change the hair appearance on the outside a reducing agent is required containing a thiol as to reduce the formation of the sulfide and disulfide bridges formation in the hair so the that any changes can be applied without the body naturally turning it back, i-e allowing easier manipulation after this hairs are to be curled physically in order to keep this a oxidizing agent is applied and then finally a keratin reformer is added to hold the shape
Answer:
Option D is correct.
H₂O + CO₂ → H₂CO₃
Explanation:
First of all we will get to know what law of conservation of mass states.
According to this law, mass can neither be created nor destroyed in a chemical equation.
This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Example:
6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂
there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.
Now we will apply this law to given chemical equations:
A) H₂ + O₂ → H₂O
There are two hydrogen and two oxygen atoms present on left side while on right side only one oxygen and two hydrogen atoms are present so mass in not conserved. This equation not follow the law of conservation of mass.
B) Mg + HCl → H₂ + MgCl₂
In this equation one Mg, one H and one Cl atoms are present on left side while on right side two hydrogen, one Mg and two chlorine atoms are present. This equation also not follow the law of conservation of mass.
C) KClO₃ → KCl + O₂
There are one K, one Cl and three O atoms are present on left side of chemical equation while on right side one K one Cl and two oxygen atoms are present. This equation also not following the law of conservation of mass.
D) H₂O + CO₂ → H₂CO₃
There are two hydrogen, one carbon and three oxygen atoms are present on both side of equation thus, mass remain conserved. Thus is correct option.
The lower the pKa<span> of a Bronsted acid, the more easily it gives up its proton. The </span>higher<span> the </span>pKa<span> of a Bronsted acid, the more tightly the proton is held, and the less easily the proton is given up.
Here we need the highest pKa, so we need to see which compound will less likely to give proton or hydrogen ion.
</span><span>Now, all Nitrogen contains a lone pair. But HALOGEN groups( F, Cl, only) being electronegative than NITROGEN [electronegativity of N=3, F=4 and Cl=3], pulls electron pair towards itself.
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The more the lone pair of nitrogen is pulled, the more strong bond between N and H will become, which means less likely to give hydrogen ion.
means high Pka
C) option is the answer because it has 3 F very close to N.
Answer:
If fixed amount of gas is heated then the volume will increase because the heat will cause the molecules of gas to move freely and increase the kinetic energy.
Explanation:
If fixed amount of gas is heated then the volume will increase because the heat will cause the molecules of gas to move freely and increase the kinetic energy.
According to the Charle's law
The volume of given amount of gas is directly proportional to the temperature at constant pressure and number of moles of gas.
Mathematical expression;
V ∝ T
V = kT
V/T = k
if volume is changed from V1 to V2 and temperature change from T1 to T2 then,
V1/T1 = k V2/T2= k
V1/T1 = V2/T2
