Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
The polynomial <span>3x2y2 − 5xy2 − 3x2y2 + 2x2 can be simplified by combining like terms.
The result is:
-5xy2 + 2x2
The polynomial is
a binomial (2 terms),
the degrees is 3
the highest order in x is 2 and the highest order in y is 2.</span>
Answer:
9/40
Step-by-step explanation:
The probability of event A happening, then event B, is the probability of event A happening times the probability of event B happening given that event A already happened.
In this case, event A is the Captain missing the pirate ship and event B is the pirate hitting the Captain's ship.
The Captain fires first, so her ship can't be sunk before she fires her cannons.
So, the probability of the Captain missing the pirate ship is
3/5
If the Captain missed the pirate ship, the pirate has a normal chance to fire back.
So, the probability of the pirate hitting the Captain's ship given the Captain missing the pirate ship is
3/8
The probability that the Captain misses the pirate ship, but the pirate hits is then the probability of the Captain missing the pirate ship times the probability of the pirate hitting the Captain's ship given the Captain missing the pirate ship.
this is 3/5 X 3/8 = 9/40
see the attached figure to better understand the problem
we have that
Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC
substitute the values in the formula
Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem
substitute the values
Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem
substitute the values
therefore
<u>the answer is</u>
the length of BD is 11.93 units
