Question

After soccer practice coach Miller goes to the roof of the school to retrieve the event soccer balls the height of the school is 3.5 m a soccer ball which leaves the roof with only a horizontal velocity of 15 m/s in the ignoring air resistance how far is the ball above the ground at 0.32 seconds

Answer 1

Answer:

50.2 cm

Explanation:

We are given that

Height ,h=3.5 m

Initial horizontal velocity,$u_x=15 m/s$

Time,t=0.32 s

We have to find the distance of ball from the ground at 0.32 s.

Initial vertical velocity,$u_y=0$

$s=u_yt+\frac{1}{2}gt^2$

Where $g=9.8 m/s^$

$s=0+\frac{1}{2}(9.8)(0.32)^2$

$s=0.502 m$

$s=0.502\times 100=50.2 cm$