answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saw5 [17]
2 years ago
12

Because the sensitivity of the human ear varies over the audio spectrum, how do many sound systems handle very high frequencies

and very low frequencies, respectively, to compensate?
1. dampen; amplify
2. amplify; amplify
3. Sound systems do nothing to compensate.
4. amplify; do nothing to
5. dampen; do nothing to
6. amplify; dampen
7. do nothing to; amplify
8. dampen; dampen
9. do nothing to; dampen
Physics
1 answer:
antoniya [11.8K]2 years ago
3 0

Answer:

Option 2.

Amplify; Amplify

Explanation:

Amplification of sound simply means increasing the loudness of the sound by modifying its electro-acoustic signals. To make very high and very low frequencies of sound audible by the human ear,  the sounds need to be amplified by the sound system amplifier.

Sound systems modify high frequencies by amplifying them, and also, they also modify low frequencies by amplifying them. This changes their wave form and brings them into the hearing range of humans.

You might be interested in
Which of the following strategies can help Earth's coal supply last longer?
ivanzaharov [21]
D. Teach the public energy conservation
7 0
2 years ago
Read 2 more answers
A passenger compartment of a rotating amusement park ride contains a bench on which a book of mass
Basile [38]

a) 120 s

b) v = 0.052R [m/s]

Explanation:

a)

The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).

The graph of the problem is missing, find it in attachment.

To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.

The first point we take is t = 0, when the position of the book is x = 0.

Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.

Therefore, the period is

T = 120 s - 0 s = 120 s

b)

The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.

The perimeter of the wheel is:

L=2\pi R

where R is the radius of the wheel.

The period of revolution is:

T=120 s

Therefore, the tangential speed of the book is:

v=\frac{L}{T}=\frac{2\pi R}{120}=0.052R

8 0
2 years ago
Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a cu
Degger [83]

Answer and Explanation:

curents i = 2.9 A

           i ' = 4.4 A

the magnitude (in T.m) of the path integral of B.dl around the window frame = μo * current enclosed

          = μo* ( i '- i )

Since from Ampere's law

where μ o = permeability of free space = 4π * 10 ^-7 H / m

plug the values we get the magnitude (in T.m) of the path integral of B.dl = ( 4π*10^-7 ) (2.9+4.4)

                                 = 1.884 * 10^-6 Tm

4 0
2 years ago
A mass of 630g is hung on a spring. Using Force = mass x gravity, what is the force of the mass, acting on the spring?
hodyreva [135]

Answer:

6.174N or roughly 6.2N

Explanation:

630g=0.63kg

F=m*g=0.63*9.8=6.174N

3 0
1 year ago
Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
Elena-2011 [213]

Answer:

Answer:

1.1 x 10^9 ohm metre

Explanation:

diameter = 1.5 mm

length, l = 5 cm

Potential difference, V = 9 V

current, i = 230 micro Ampere = 230 x 10^-6 A

radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m

Let the resistivity is ρ.

Area of crossection

A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2

Use Ohm's law to find the value of resistance

V =  i x R

9 = 230 x 10^-6 x R

R = 39130.4 ohm

Use the formula for the resistance

R=\rho \frac{l}{A}

\rho =\frac{RA}{l}

\rho =\frac{39130.4\times 0.05}{1.766\times 10^{-6}}

ρ = 1.1 x 10^9 ohm metre

Explanation:

7 0
2 years ago
Other questions:
  • Physics Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    7·2 answers
  • The total energy of a 0.050 kg object travelling at 0.70 c is
    13·1 answer
  • Which type of listening response includes the use of head nods, facial expressions, and short utterances such as "uh-huh" that s
    8·1 answer
  • A fishing boat accidentally spills 3.0 barrels of diesel oil into the ocean. each barrel contains 42 gallons. if the oil film on
    12·1 answer
  • g A projectile is launched with speed v0 from point A. Determine the launch angle ! which results in the maximum range R up the
    12·1 answer
  • The gas tank of Dave’s car has a capacity of 12 gallons. The tank was 38 full before Dave filled it to capacity. It cost him $2.
    8·2 answers
  • The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
    12·1 answer
  • The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the tot
    6·1 answer
  • A small object with mass m, charge q, and initial speed v0 = 5.00 * 103 m>s is projected into a uniform electric field betwee
    13·1 answer
  • Tech A says that some electric actuators are positioned by an A/C ECU which checks the air flow with sensors. Tech B says that e
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!