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2 years ago

14

Haley noticed a small spot on her skin that turned out to be skin cancer. Which treatment is her doctor most likely to use?

1 answer:

vova2212 [387]2 years ago

6 0

Answer:

Radiation therapy

Explanation:

Her doctor is more likely to use radiation therapy to irradiate the cancerous cells on the skin. The doctor uses soft x-rays to kill the cancer cells. The therapy is used even after surgery as it has the advantage of delaying the advancement of future cancers.

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Which of the following would increase the strength of an electromagnet ?

AleksAgata [21]

<span>More coils of wire around the magnetic material. More current through the wire</span>

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2 years ago

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Saturn's moon Mimas has an orbital period of 82,800 s at a distance of 1.87x10^8m from Saturn. Using m central m= (4n^2d^3/GT^2)

FromTheMoon [43]

5.65×10^26kg here you go

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2 years ago

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While dangling a hairdryer by its cord, you observe that the cord is vertical when the hairdryer isoff and, once it is turned on

jekas [21]

Answer:

The speed of the air leaving the hairdryer is 10m/s.

Explanation:

The thrust that the dryer produces is what keeps it elevated at an angle of 5° from the vertical; therefore, from the force diagram we get

$(1).\: tan (5^o) = \dfrac{F_t}{Mg}$

putting in $M =0.420kg$ , $g = 9.8m/s^2$ and solving for $F_t$ we get:

$F_t = Mg\:tan(5^o)$

$F_t = (0.420kg)(9.8m/s^2)\:tan(5^o)$

$\boxed{F_t = 0.3601N.}$

Now, this thrust produced is related to to the air ejection speed $v$ by the relation

$(2).\: F_t = v\dfrac{dM}{dt}$

where $dM/dt$ is the rate of air ejection which we know is

$0.06m^3/2s = 0.03m^3/s$

and since $1m^3 = 1.2kg$ ,

$0.03m^3/s \rightarrow 0.036kg/s$

$\dfrac{dM}{dt} = 0.036kg/s,$

putting this into equation (2) and the value of $F_t$ we get:

$0.3601N = 0.036v$

which gives

$v= \dfrac{0.3601}{0.036}$

$\boxed{v =10m/s.}$

which is the speed of the air ejected.

6 0

2 years ago

A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that

nevsk [136]

Answer:

Option (c) will be correct answer that is it will go 1.6 m

Explanation:

We have given that conveyor has the velocity u = 3.1 m/sec

Mass of the robot = 10 kg

static friction coefficient = 0.5 and kinetic friction coefficient = 0.3

Acceleration due to gravity g = 9.8 $m/sec^2$

Acceleration a = kinetic friction coefficient ×g = 0.3×9.8 = 2.94 $m/sec^2$

Now according to third equation of motion

$v^2=u^2+2as$

Finally velocity of the conveyor will be zero

So $0^2=3.1^2-2\times 2.94\times s$

s = 1.6 m

So option (c) is correct option

4 0

2 years ago

A man stands on his balcony, 130 feet above the ground. He looks at the ground, with his sight line forming an angle of 70° with

jenyasd209 [6]

Answer:

d = 380 feet

Explanation:

Height of man = perpendicular= 130 feet

Angle of depression = ∅ = 70 °

distance to bus stop from man = hypotenuse = d = 130 sec∅

As sec ∅ = 1 / cos∅

so d = 130 sec∅ or d = 130 / cos∅

d = 130 / cos(70°)

d = 380 feet

8 0

2 years ago