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adell [148]
2 years ago
7

A student constructs a simple constant volume gas thermometer and calibrates it using the boiling point of water, 100°C, and the

freezing point of a specific brine solution, -19°C. The pressures measured at the calibration points are 1.366 atm and 0.9267 atm, respectively. From these data, what temperature will the student calculate, in degrees Celsius, for the value of absolute zero?
Physics
1 answer:
just olya [345]2 years ago
4 0

Answer:

The pressure corresponding to the absolute zero temperature is 0.997atm.

Explanation:

To solve this question, you draw a straight vertical line with the boiling point temperature and pressure on top of the line and the freezing point temperature and pressure on the lower part. The absolute temperature somewhere in the middle of the line with the pressure to be obtained.

So, we have;

0- (-19) / 100 - (-19) = P - 0.9267 / 1.366 - 0.9267

19 / 119 = P - 0.9267 / 0.4393

Cross multiply, we have

19 * 0.4393 = 119(P -0.9267)

8.3467 = 119P - 110.2773

119P = 118.624

P = 0.997 atm

So at 0°C, the pressure of the thermometer is 0.997atm.

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Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo
bagirrra123 [75]
By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>
5 0
2 years ago
Describe the distribution of wdiff in terms of its center, shape, and spread, including any plots you use
melisa1 [442]

Answer:

Figure attached

We can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

Explanation:

We can use the following R code to obtain the data for wdiff:

source("http://www.openintro.org/stat/data/cdc.R")  #obtain the info

nrow(cdc) # number of elements

names(cdc)  # obtain the name for the variable

[1] "genhlth"  "exerany"  "hlthplan" "smoke100" "height"   "weight"   "wtdesire" "age"      

[9] "gender"  

wdiff represent the difference between desired weight (wtdesire) and current weight (weight) and we can obtain the data with the following code:

wdiff <- (cdc$weight-cdc$wtdesire)

And now we can create the histogram with this code

hist(wdiff,xlim =c(-100,150))

> mean(wdiff)

[1] 14.5891

> median(wdiff)

[1] 10

And the result is on the figure attached.

And we can conclude that majority of the values are positive. And we can say that is skewed to the right because the Median< Mean is and we have most of the values at the left of the distribution.

3 0
2 years ago
A superman cyclist rode a bike uphill at 20 miles/hour for two hours. To sustain this constant speed the cyclist was exerting 50
NeX [460]

Answer:

1.056 x 10⁷ lb-ft

Explanation:

v = Speed of the bike = 20 mph

t = time of travel = 2 h

d = distance traveled by cyclist

Distance traveled by cyclist is given as

d = v t

d = (20) (2)

d = 40 miles

We know that, 1 mile = 5280 ft

d = 40 (5280) ft

d = 211200 ft

F = force applied by cyclist = 50 lb

W = work done by cyclist

Work done by cyclist is given as

W = F d

W = (50) (211200)

W = 1.056 x 10⁷ lb-ft

5 0
2 years ago
The lighting needs of a storage room are being met by six fluorescent light fixtures, each fixture containing four lamps rated a
Amanda [17]

Answer:

amount of energy  = 4730.4 kWh/yr

amount of money = 520.34 per year

payback period = 0.188 year

Explanation:

given data

light fixtures = 6

lamp = 4

power = 60 W

average use = 3 h a day

price of electricity = $0.11/kWh

to find out

the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66

solution

we find energy saving by difference in time the light were

ΔE = no of fixture × number of lamp × power of each lamp × Δt

ΔE is amount of energy save and Δt is time difference

so

ΔE = 6 × 4 × 365 ( 12 - 9 )

ΔE = 4730.4 kWh/yr

and

money saving find out by energy saving and unit cost that i s

ΔM = ΔE × Munit

ΔM = 4730.4 × 0.11

ΔM = 520.34 per year

and

payback period is calculate as

payback period = \frac{excess initial cost}{\Delta M}

payback period = \frac{32 + 66}{520.34}

payback period = 0.188 year

8 0
2 years ago
Light is propagated as a transverse wave. For this reason, sunglasses, ski goggles and camera lenses can restrict the vibration
Flura [38]

Polerization is the anwser

6 0
2 years ago
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