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erastovalidia [21]
2 years ago
3

A child with a weight of 140 N swings on a playground swing attached to 2.10 m long chains. What is the gravitational potential

energy (in J) of the child-earth system relative to the child's lowest position at the following times?
a. when the ropes are horizontal
b. when the ropes make a 25.0° angle with the vertical
c. when the child is at the bottom of the circular arc
Physics
2 answers:
statuscvo [17]2 years ago
6 0

Answer:

a). When the ropes are horizontal

Potential energy= 294 Joules

b. when the ropes make a 25.0°

Potential energy= 124.25 Joules

C.when the child is at the bottom of the circular arc

Potential energy= 140 Joules

Explanation:

a). When the ropes are horizontal.

Potential energy = mgh

Potential energy= 140*2.10

Potential energy= 294 Joules

b. when the ropes make a 25.0°

Potential energy= mghsin(tita)

Potential energy= 140*2.10*sin(25)

Potential energy= 124.25 Joules

C.when the child is at the bottom of the circular arc.

Potential energy= mg

I.e weight of the child is the energy he possesses because of no height.

gogolik [260]2 years ago
6 0

Answer:

a). Gravitational Potential energy= 294 Joules

b). when the ropes make a 25.0°

Gravitational Potential energy= 27.55 Joules

C).Gravitational Potential energy= 0 Joules

Explanation:

GPE (gravitational potential energy ) is always relative to some zero reference point.  For swings, it makes sense to set GPE = 0 at the bottom of the swing's arc where theta = 0 deg relative to the vertical.

In general GPE (gravitational potential energy ) = mgh;

where mg = 140 N is the weight of the child with mass m,

g is the gravity field, and

h is the height above the zero reference.

In general, from ordinary trig, we have h = L(1 - cos(theta))

where L = 2.1 m is the length of each rope.  

Gravitational Potential energy = mgh

Gravitational Potential energy

= 140 × L(1 - cos(90))

= 140 × 2.10(1 - 0)

= 294joules

b)  GPE = 140*2.1(1 - cos(25))

Gravitational Potential energy

= 140 × L(1 - cos(25))

= 140 × 2.10(1 - 0.9063)

= 140 × 2.10(0.0937)

= 140 × 0.19677

=27.55 joules

c)

GPE = 0  or

= 140*2.1(1 - cos(0))

= 0

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