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Softa [21]
2 years ago
7

Consider the diagram of the basic structure of a bacterium. A diagram of a bacterium is labeled. Part A is the cell membrane, pa

rt B is the flagellum, part C is the nucleoid, and part D is the pilus. Which of the labeled structures in the image allows bacteria to exchange genetic material and thus evolve to be better pathogens? A B C D HURRY!!! 100 POINTS!!!!
Chemistry
2 answers:
Vesnalui [34]2 years ago
7 0

Answer:

It is part c

Explanation:

butalik [34]2 years ago
7 0

Answer:

the answer is D

Explanation:

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If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef
marysya [2.9K]

<u>Answer:</u> The amount of time required by chlorine gas to effuse is 19 seconds.

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

\text{Rate}=\frac{n}{t}

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So,

\left(\frac{\frac{n_{Cl_2}}{t_{Cl_2}}}{\frac{n_{I_2}}{t_{I_2}}}\right)=\sqrt{\frac{M_{I_2}}{M_{Cl_2}}}

We are given:

Moles of iodine gas = 0.15 moles

Moles of chlorine gas = 0.15 moles

Time taken by iodine gas = 36 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

\left(\frac{\frac{0.15}{t_{Cl_2}}}{\frac{0.15}{36}}\right)=\sqrt{\frac{254}{71}}\\\\\frac{0.15}{t_{Cl_2}}\times \frac{36}{0.15}=1.89\\\\t=19s

Hence, the amount of time required by chlorine gas to effuse is 19 seconds.

6 0
2 years ago
What mass of silver ag which has an atomic mass of 107.87 amu contains the same number of atoms contained in 10.0g of boron b wh
Masteriza [31]

To contain the same number of atoms also mean to contain the same number of moles. So let us say that X is the mass of Silver Ag required, so that:

X / 107.87 = 10 / 10.81

<span>X = 99.79 g</span>

6 0
2 years ago
Read 2 more answers
How much 2 M HBr is needed to neutralize 380 mL of 0.1 M NH4OH?
Nata [24]

Answer:

19ml

Explanation:

trust me

8 0
2 years ago
Imagine you needed to identify if an object has undergone a physical change or a chemical change. What information would you nee
pishuonlain [190]
How it looks. basically the thing that tells you how it change. for example if an ice cube was melted (heat), it only changed physically not chemically as the h20 molecules are still there. however lets say you burn woos— you cant get that would back. its ash now and it has changed chemically.
7 0
2 years ago
Two gases, A and B, are at equilibrium in a sealed cylinder. Individually, gas A is colorless, while gas B is dark colored. The
Dmitriy789 [7]

Answer:

(a) color

(b) endothermic

(c)

b The ΔH value would have the same magnitude value but opposite sign.

c The K expression would be inverted.

Explanation:

Let's consider the following reaction at equilibrium.

      A(g) ⇄ 2 B(g)

colorless    dark colored

<em>(a) The cylinder should appear (color or colorless)</em>

At equilibrium, there is a mixture of A and B, so the cylinder should appear colored.

<em>(b) When the system is cooled, the cylinder's appearance becomes very light colored. Therefore, the reaction must be (endothermic or exothermic)</em>

According to Le Chatelier's Principle when a perturbation is made to a system at equilibrium it will react to counteract such effect. When the system is cooled, it will tend to increase the temperature by releasing heat. In this case, the reaction is endothermic so when the reverse reaction is favored, colorless A is favored as well.

<em>Suppose the reaction equation were written as follows: 2 B(g) ⇄ A(g) </em>

<em>(c) Which of these statements would then be true?</em>

<em>a The value of K would not change.</em> FALSE. The new K would be the inverse of the direct K.

<em>b The ΔH value would have the same magnitude value but opposite sign. </em>TRUE. This is stated by Lavoisier-Laplace Law.

<em>c The K expression would be inverted.</em> TRUE. What was product before now is reactant and vice-versa.

<em>d The color of the cylinder would be darker.</em> FALSE. Changing the way the reaction is expressed has no effect on the equilibrium.

7 0
2 years ago
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