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Arlecino [84]
2 years ago
4

A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if

a loose part were released from the spacecraft without a push in any direction, what would happen to it?
A.
It would slowly coast to a stop.
B.
It would head off on its own trajectory.
C.
It would stop immediately as soon as it was no longer in contact with the probe.
D.
It would continue along with the spacecraft.
Physics
2 answers:
dezoksy [38]2 years ago
7 0
D. It would continue along with the spacecraft
Leni [432]2 years ago
5 0
I think the answer is c
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The environment affects people, but people don't affect the environment.<br><br><br>TRUE OR FALSE
Drupady [299]

Answer: False

Explanation:

The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.

Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.

5 0
2 years ago
Microwave ovens emit microwave energy with a wavelength of 12.6 cm. what is the energy of exactly one photon of this microwave r
Helga [31]

We need the frequency of the photon, it is v = c/ λ

Where c is 3 x 10^8 ms^-1 and λ is the wave length

We also need the expression of connecting frequency to energy of photon 

which is E = hv where h is Planck’s constant

Combining the two equations will give us:

E = h x c/λ

Inserting the values, we will have:

E = 6.626 x 10^-34 x 3 x 10^8 / 0.126

E = 1.578 x 10^ -24 J

7 0
2 years ago
Read 2 more answers
A 0.900 kg ornament is hanging by a 1.50 m wire when the ornament is suddenly hit by a 0.400 kg missile traveling horizontally a
just olya [345]

Explanation:

The given data is as follows.

  Mass of the ornament (m_{1}) = 0.9 kg

  Length of the wire (l) = 1.5 m

 Mass of missile (m_{2}) = 0.4 kg

 Initial speed of missile (u_{2}) = 12 m/s

         r = 1.5 m

According to the law of conservation of momentum,

                   p_{i} = p_{f}  

     m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

Putting the given values into the above formula as follows.

          m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

         0.9 \times 0 + 0.4 \times 12 = (0.9 + 0.4)v

              0 + 4.8 = 1.3v

                  v = 3.69 m/s

Now, the centrifugal force produced is calculated as follows.

            F_{c} = (m_{1} + m_{2}) \times \frac{v^{2}}{r}

                       = (0.9 + 0.4) \times \frac{(3.69)^{2}}{1.5}

                       = 11.80 N

Hence, tension in the wire is calculated as follows.

              T = F_{c} + (m_{1} + m_{2})g

                 = 11.80 N + (0.9 + 0.4) \times 9.8

                 = 24.54 N

Thus, we can conclude that tension in the wire immediately after the collision is 24.54 N.

4 0
2 years ago
Which of the following quantities provide enough information to calculate the tension in a string of mass per unit length μ that
Bad White [126]

Answer:

A. the wave speed v and Wavelength

Explanation:

Given that

Mass density per unit length=μ

Frequency = f

The velocity V given as

\mu=\dfrac{T}{V^2}\ kg/m

V=\sqrt{\dfrac{T}{\mu}}

T=Tension

V=Velocity

V= f λ

λ=Wavelength

Therefore to find the tension ,only wavelength and speed is required.

The answer is A.

8 0
2 years ago
25 A plank AB 3.0 m long weighing 20 kg and
Eva8 [605]

Answer:

Ahhhhhhhhhgghh ahhhhhhh

3 0
2 years ago
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