gravitational potential energy is given by formula
here we need to compare the gravitational potential energy of stone 2 with respect to stone 1
so we will say
given that
now we have
A loop of wire with a weight of 0.55 N is oriented vertically and carries a current I = 2.25 A. A segment of the wire passes thr
ough a magnetic field directed into the plane of the page as shwon. The net force on the wire is measured using a balance and found to be zero. What is the magnitude of the magnetic field?
1 answer:
Answer:
Incomplete question.
Check the diagram given in attachment
Explanation:
Given that,
Weight w= 0.55N
Current I = 2.25A
Length = 0.2m
The net force is 0 N
Apply Newton second law
Fnet = ΣF
ΣF = 0
The weight is acting downward outside the plane
Then,
Magnetic Force — Weight = 0
F — W = 0
F = W
Magnetic force is given as
F = iLB
Therefore
iLB =W
B = W / iL
B = 0.55 / (2.25 × 0.2)
B = 1.22 T
The magnitude of the magnetic field is 1.22 T
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Answer:
the tension in the rope between the boxes is equal to 88 N
Explanation:
given,
the force applied on one body F = 176 N
When two bodies are moving on horizontal plane at constant velocity then their kinetic friction (f k) is equal to applied force F
According to newton third law the resultant force acting on one body is equal to the resultant force acting on the another body.
T is the tension in the rope
T - F = - (T - F)
T - 176 = - (T - 0)
2 T = 176
T = 176/2 = 88 N
so, the tension in the rope between the boxes is equal to 88 N