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torisob [31]
2 years ago
6

A stone is held at a height h above the ground. A second stone with four times the mass of the first one is held at the same hei

ght. The gravitational potential energy of the second stone compared to that of the first stone is
Physics
1 answer:
QveST [7]2 years ago
5 0

gravitational potential energy is given by formula

U = mgh

here we need to compare the gravitational potential energy of stone 2 with respect to stone 1

so we will say

\frac{U_2}{U_1} = \frac{m_2gh}{m_1gh}

\frac{U_2}{U_1} =\frac{m_2}{m_1}

given that

m_2 = 4 m_1

now we have

\frac{U_2}{U_1} = 4

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A block of mass 2.00 kg is initially at rest at x=0 on a slippery horizontal surface for which there is no friction. Starting at
Allisa [31]

Answer:

   x = 1,185 m ,     t = 4/3 s ,  F = - 4 N

Explanation:

For this exercise we use Newton's second law

         F = m a = m dv /dt

        β - α t = m dv / dt

        dv = (β – α t) dt

     

We integrate

        v = β t - ½ α t²

We evaluate between the lower limits v = v₀ for t = 0 and the upper limit v = v for t = t

       v-v₀ = β t - ½ α t²

the farthest point of the body is when v = v₀ = 0

  0 = β t - ½ α t²

  t = 2 β / α

  t = 2 4/6

  t = 4/3 s

Let's find the distance at this time

   v = dx / dt

   dx / dt = v₀ + β t - ½ α t2

   dx = (v₀ + β t - ½ α t2) dt

We integrate

   x = v₀ t + ½ β t - ½ 1/3 α t³

   x = v₀ 4/3 + ½ 4 (4/3)² - 1/6 6 (4/3)³

The body comes out of rest

    x = 3.5556 - 2.37

    x = 1,185 m

The value of force is

    F = β - α t

    F = 4 - 6 4/3

   F = - 4 N

8 0
1 year ago
The statements below are all true. Some of them represent important reasons why the giant impact hypothesis for the Moon’s forma
Molodets [167]

Answer:

the order of importance must be     b e a f c

Explanation:

Modern theories indicate that the moon was formed by the collision of a bad plant with the Earth during its initial cooling period, due to which part of the earth's material was volatilized and as a ring of remains that eventually consolidated in Moon.

Based on the aforementioned, let's analyze the statements in order of importance

b) True. Since the moon is material evaporated from Earth, its compassion is similar

e) True. If the moon is material volatilized from the earth it must train a finite receding speed

a) True. The solar system was full of small bodies in erratic orbits that wander between and with larger bodies

f) False. The moon's rotation and translation are equal has no relation to its formation phase

c) false. The amount of vaporized material on the moon is large

Therefore, the order of importance must be

         b e a f c

5 0
2 years ago
1. Three confused sled dogs are trying to pull a sled across the Alaskan snow. Tim pulls east with a force of 42 N; Sam also pul
Bumek [7]

Answer:

Explanation:

According to the statement, three confused sleigh dogs are trying to pull a sled across the Alaskan snow.  

Forces in same direction gets added , so 35N + 42N=77N  and the Net Force is 77N -53N as it is acting in opposite direction.

Net force is 25N in east to the maximum without any hassle.

-------------------------------------------------------------------------------------------------

thankyou : )

6 0
1 year ago
Two students, sitting on frictionless carts, push against each other. Both are initially at rest and the mass of student 1 and t
Zepler [3.9K]

Answer:

  v₂ = v/1.5= 0.667 v

Explanation:

For this exercise we will use the conservation of the moment, for this we will define a system formed by the two students and the cars, for this isolated system the forces during the contact are internal, therefore the moment conserves.

Initial moment before pushing

    p₀ = 0

Final moment after they have been pushed

    p_{f} = m₁ v₁ + m₂ v₂

   p₀ =  p_{f}

   0 = m₁ v₁ + m₂ v₂

   m₁ v₁ = - m₂ v₂

Let's replace

   M (-v) = -1.5M v₂

   v₂ = v / 1.5

  v₂ = 0.667 v

6 0
1 year ago
Coffee is poured at a uniform rate at 20 cm3 / s into a cup whose inside is shaped like a truncated cone. if the upper and lower
Vladimir [108]

Let the cup is filled to height h after some time

now the total volume of coffee filled in the cup is given as

\frac{2}{y} = \frac{4}{6+y}

2y = 6 + y

y = 6 cm

now volume of the coffee will be

V = \frac{1}{3}\pi r^2(y + 6) - \frac{1}{3}\pi 2^2 (6)

here we know that

\frac{r}{y+6} = \frac{2}{6}

r = \frac{y+6}{3}

V = \frac{1}{3}\pi (\frac{y+6}{3})^2(y+6) - \frac{1}{3}\pi 2^2(6)

now we know that volume flow rate is given as

Q = \frac{dV}{dt}

20 cm^3/s = \frac{1}{3}\pi (\frac{1}{9})(3(y+6)^2)\frac{dy}{dt}

20 \times 9 = \pi (y + 6)^2 v

here y = 3 cm

180 = \pi (9)^2 v

v = 0.71 cm/s

so water will rise up with speed 0.71 cm/s


5 0
2 years ago
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