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4vir4ik [10]
1 year ago
13

Assuming motion is on a straight path, what would result in two positive components of a vector?

Physics
2 answers:
Aliun [14]1 year ago
3 0
Answer: option <span>A) a train moving north of east at an angle of 25°
</span>

Explanation:

1) You need to choose your axis. In this case North is vertical and positive, South is vertical and negative, East is horizontal and positive, and West is horizontal and negative.

2) The vector with the two positive components is a vector in the first quadrant (North and East). That is what North of East 25° means.

3) Regarding the other options:

<span>B) a bus moving North of East at an angle of 95°: since the angle is greater tnan 90° the vector is in the second quadrant: its horizontal component is negative.
</span>
<span /><span>
</span><span> C) a boat moving South of West at an angle of 40°: this is in the third quadrant: the two components are negative.</span>
<span /><span>
</span><span> D) a car moving south of west at an angle of 10°: as in the option C), this is in the third quadrant: the two components are negative.
</span>

avanturin [10]1 year ago
3 0

A.

Two positive components means that the vector should lie in the first quadrant and not be parallel to the x or y axis; the only option that satisfies this is A.

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A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at the 30 cm mark. What is the we
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Answer:

The weight of the meter rule is equal to the weight W placed at the 30cm mark

Explanation:

Detailed explanation and calculation is shown in the image

4 0
1 year ago
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ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself o
shtirl [24]

Q: ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself off in the opposite direction at 60 m/s. What is the magnitude of the average force the wall exerts on Ken during this rapid maneuver

Answer:

-6461.54 N

Explanation:

From Newton's Fundamental equation,

F = m(v-u)/t.................... Equation 1

Where F = Force exerted in sonic, m = mass of ken, v = final velocity, u = initial velocity, t = time.

Given: m = 0.75 kg, v = - 60 m/s (opposite direction), u = 52 m/s, t = 13 ms = 0.013 s

Substitute into equation 1

F = 0.75(-60-52)/0.013

F = 0.75(-112)/0.013

F = -84/0.013

F = -6461.54 N

Note: The negative sign tells that the force act in opposite direction to the initial motion of ken.

Hence the magnitude of the average force of the wall = -6461.54 N

4 0
1 year ago
Waves inwhich the particles vibrate at right angles to direction is called
liberstina [14]
When the particles<span> of a medium are </span>vibrating at right angles<span> to the </span>direction<span> of energy transport, then the </span>wave<span> is a ____ </span>wave<span>. In transverse </span>waves<span>, </span>particles<span> of the medium </span>vibrate<span> to and from in a </span>direction<span> perpendicular to the </span>direction<span> of energy transport. </span>
5 0
1 year ago
An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m
aniked [119]

Answer: The released electromagnetic wave will travel in +y direction

Explanation:

It should be noted that, in a situation, whereby an excited hydrogen atom releases an electromagnetic wave to return to its normal state. And it's also evident that the futuristic dual electric/magnetic field tester on the electromagnetic wave to find the directions of the electric field and magnetic field is used. Eventually, your device tells you that the electric field is pointing in the positive y direction and the magnetic field is pointing in the positive x direction. Therefore, the released electromagnetic wave will travel in +y direction.

7 0
1 year ago
Steve and Elsie are camping in the desert, but have decided to part ways. Steve heads north, at 8 AM, and walks steadily at 2 mi
polet [3.4K]

Answer:

2.57 hours

Explanation:

Let t (hours) be the times it takes for Elsie to walk until they are 25 miles apart. Since Steve is 2 hours earlier, the time it takes for him is t + 2

Distance Steve covers to the North is s_s =  2(t + 2)

Distance that Elsie covers to the West is s_e = 2.5t

Distance between Steve and Elsie is

\sqrt{s_s^2 + s_e^2} = \sqrt{(2(t+2))^2 + (2.5t)^2} = 25

We can solve for t by raise the power on both sides to the 2nd

(2(t+2))^2 + (2.5t)^2 = 25^2 = 625

4(t+2)^2 + 6.25t^2 = 625

4(t^2 + 4t + 4) + 6.25t^2 = 625

10.25t^2 + 16t - 609 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{-16\pm \sqrt{(16)^2 - 4*(10.25)*(-109)}}{2*(10.25)}

t= \frac{-16\pm68.74}{20.5}

t = 2.57 or t = -4.13

Since t can only be positive we will pick t = 2.57  hours

8 0
1 year ago
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