A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at the 30 cm mark. What is the we
ight of the meter stick?
2 answers:
Answer:
The answer is W
Explanation:
Since the metre stick is a metre rule, the length of the stick is 1m which is equivalent to 100cm.
Check the attachment for diagram.
Note that the weight of the metre rule will be positioned at the centre of the metre rule i.e at 50cm from one end of the metre rule as shown in the diagram.
Using the principle of moments to solve for W. It States that the sum of clockwise moments is equal to the sum of anticlockwise moments.
Since Moment = Force × perpendicular distance
Let the weight of the meter rule be M
Clockwise moment = M × 10
Anticlockwise moment = W × 10
Equating both to get M;
10M = 10W
M = W
This shows that the weight M of the metre rule is equal to the weight placed at the 30cm mark
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a) 120 s
b) v = 0.052R [m/s]
Explanation:
a)
The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).
The graph of the problem is missing, find it in attachment.
To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.
The first point we take is t = 0, when the position of the book is x = 0.
Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.
Therefore, the period is
T = 120 s - 0 s = 120 s
b)
The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.
The perimeter of the wheel is:
where R is the radius of the wheel.
The period of revolution is:
Therefore, the tangential speed of the book is:
Data:
Centripetal Force = ? (Newton)
m (mass) = 68 Kg
s (speed) = 3.9 m/s
R (radius) = 6.5 m
Formula:
Solving:
Answer:
<span>B.159 N</span>
Centripetal Force = ? (Newton)
m (mass) = 68 Kg
s (speed) = 3.9 m/s
R (radius) = 6.5 m
Formula:
Solving:
Answer:
<span>B.159 N</span>