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Alex_Xolod [135]
1 year ago
13

A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at the 30 cm mark. What is the we

ight of the meter stick?

Physics
2 answers:
lora16 [44]1 year ago
6 0

Answer:

The answer is W

Explanation:

Since the metre stick is a metre rule, the length of the stick is 1m which is equivalent to 100cm.

Check the attachment for diagram.

Note that the weight of the metre rule will be positioned at the centre of the metre rule i.e at 50cm from one end of the metre rule as shown in the diagram.

Using the principle of moments to solve for W. It States that the sum of clockwise moments is equal to the sum of anticlockwise moments.

Since Moment = Force × perpendicular distance

Let the weight of the meter rule be M

Clockwise moment = M × 10

Anticlockwise moment = W × 10

Equating both to get M;

10M = 10W

M = W

This shows that the weight M of the metre rule is equal to the weight placed at the 30cm mark

statuscvo [17]1 year ago
4 0

Answer:

The weight of the meter rule is equal to the weight W placed at the 30cm mark

Explanation:

Detailed explanation and calculation is shown in the image

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A submarine periscope uses two totally reflecting 45-45-90 prisms with total internal reflection on the sides adjacent to the 45
Likurg_2 [28]

Answer

Given,

Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.

refractive index of water, n_a = 1.33

refractive index of glass, n_g = 1.52

When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.

7 0
1 year ago
A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x
sattari [20]
If the force were constant or increasing, we could guess that the speed of the sardines is increasing. Since the force is decreasing but staying in contact with the can, we know that the can is slowing down, so there must be friction involved.
Work is the integral of (force x distance) over the distance, which is just the area under the distance/force graph.
The integral of exp(-8x) dx that we need is (-1/8)exp(-8x) evaluated from 0.47 to 1.20 .

I get 0.00291 of a Joule ... seems like a very suspicious solution, but for an exponential integral at a cost of 5 measly points, what can you expect. On the other hand, it's not really too unreasonable. The force is only 0.023 Newton at the beginning, and 0.000067 newton at the end, and the distance is only about 0.7 meter, so there certainly isn't a lot of work going on. The main question we're left with after all of this is: Why sardines ? ?
6 0
1 year ago
Two roads intersect at right angles, one going north-south, the other east-west. an observer stands on the road 60 meters south
Sloan [31]

observer is standing at distance d = 60 m south from the intersection

cyclist is travelling at speed v = 10 m/s

now after t = 8 s its displacement from intersection is given by

x = 10*8 = 80 m

so the position of cyclist makes an angle with the observer

\theta = tan^{-1}\frac{80}{60} = 53 degree

now the component of velocity of cyclist along the line joining its position with the observer is given as

v = v_o cos\phi

here

\phi = 90 -\theta

\phi = 90 - 53 = 37 degree

v = 10 cos37 = 8 m/s

so at this instant cyclist is moving away with speed 8 m/s

7 0
2 years ago
Read 2 more answers
A person is nearsighted with a far point of 75.0 cm. a. What focal length contact lens is needed to give him normal vision
BigorU [14]

Complete Question

The  complete question is  shown on the first uploaded image  

Answer:

a

  f=  -75 \ cm =  - 0.75 \ m

b

  P  =  -1.33 \ diopters

Explanation:

From the question we are told that

    The  image distance is  d_i =  -75 cm

The value of the image is negative because it is on the same side with the corrective glasses

    The  object distance is  d_o =  \infty

The  reason object distance  is because the object father than it being picture by the eye

General focal length is mathematically represented as

              \frac{1}{f}  =  \frac{1}{d_i}  -   \frac{1}{d_o}

substituting values

             \frac{1}{f}  =  \frac{1}{-75}  -   \frac{1}{\infty}

=>         f=  -75 \ cm =  - 0.75 \ m

Generally the power of the corrective lens is  mathematically represented as

        P  =  \frac{1}{f}

substituting values

       P  =  \frac{1}{-0.75}

        P  =  -1.33 \ diopters

7 0
1 year ago
Two large, flat metal plates are separated by a distance that is very small compared to their height and width. The conductors a
mote1985 [20]

Answer:

E=0

Explanation:

Electric field due to each thin sheet of charge=\sigma/2\varepsilon

let us say the right plate has positive charge density \varepsilonand left sheet has a negative charge density -\varepsilon .

In the region between the plates,the electric field due to each plate is in same direction,

E=\sigma/2\varepsilon-(-\sigma/2\varepsilon)

E=\sigma/\varepsilon

in the region outside the plates, the field due to the plates is in opposite directions

E=-\sigma/2\varepsilon-(-\sigma/2\varepsilon)

E=-\sigma/2\varepsilon+\sigma/2\varepsilon

E=0

4 0
1 year ago
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