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Alex_Xolod [135]
2 years ago
13

A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at the 30 cm mark. What is the we

ight of the meter stick?

Physics
2 answers:
lora16 [44]2 years ago
6 0

Answer:

The answer is W

Explanation:

Since the metre stick is a metre rule, the length of the stick is 1m which is equivalent to 100cm.

Check the attachment for diagram.

Note that the weight of the metre rule will be positioned at the centre of the metre rule i.e at 50cm from one end of the metre rule as shown in the diagram.

Using the principle of moments to solve for W. It States that the sum of clockwise moments is equal to the sum of anticlockwise moments.

Since Moment = Force × perpendicular distance

Let the weight of the meter rule be M

Clockwise moment = M × 10

Anticlockwise moment = W × 10

Equating both to get M;

10M = 10W

M = W

This shows that the weight M of the metre rule is equal to the weight placed at the 30cm mark

statuscvo [17]2 years ago
4 0

Answer:

The weight of the meter rule is equal to the weight W placed at the 30cm mark

Explanation:

Detailed explanation and calculation is shown in the image

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Explanation:

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charge, q1 =5.00μC, is at the origin, a second charge, q2= -3μC, is on the x-axis 0.800m from the origin. find the electric fiel
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Answer:

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In vector form

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= √(26.78² + 165.76² ) x 10³ N /C

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